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Ad libitum [116K]

3 years ago

11

An event has 15 adults and 12 children. The event planner wants to make each table identical, with the same combination of adult

s and children and no people left over. What is the greatest number of tables the planner can set up?

2 answers:

Andru [333]3 years ago

8 0

3 tables with 4 children and 5 adults

natka813 [3]3 years ago

7 0

5 adults and 4 children. 3 Tables.

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Complete the square than convert to vertex form. y=2x^2+8x-9

8_murik_8 [283]

$y=2x^2+8x-9\\D=b^2-4ac\\D=64-4(2)(-9)\\D=64+72 > 0$

There are 2 roots so the only way to complete the square is,

$y=2x^2+8x-9\\y=2[(x^2+4x)]-9\\y=2[(x^2+4x+4)-4]-9\\y=2[(x+2)^2-4]-9\\y=2(x+2)^2-8-9\\y=2(x+2)^2-17$

Just factor 2 out of 2x^2+8x (just ignore the -9) then find the number that will make the terms be able to complete the square.

then complete the square and multiply 2 inside the brackets.

subtraction as you already get the vertex form and know how to complete the square.

Vertex Form: $y=2(x+2)^2-17$

3 0

3 years ago

Factor x3-2x2-9x+18 completely if(x+3) is a factor

Charra [1.4K]

Factor x^3 -2x^2-9x+18

= x^2(x - 2) - 9(x - 2)

= (x^2 - 9)(x -2)

= (x + 3 )(x - 3)(x - 2)

So (x+3) is a factor

6 0

4 years ago

Read 2 more answers

Help please thank you sm

vitfil [10]

The correct answer is 5/21

5 0

3 years ago

Simplify sqrt(45/7y)

Alex_Xolod [135]

8.2y that the cayse 45 is 7 byt 8.2

7 0

3 years ago

3. Students arrive at an ATM machine in a random pattern with an average inter-arrival time of 3 minutes. The length of transact

svp [43]

Answer:

The probability that a student arriving at the ATM will have to wait is 67%.

Step-by-step explanation:

This can be solved using the queueing theory models.

We have a mean rate of arrival of:

$\lambda=1/3\,min^{-1}$

We have a service rate of:

$\mu=1/2\,min^{-1}$

The probability that a student arriving at the ATM will have to wait is equal to 1 minus the probability of having 0 students in the ATM (idle ATM).

Then, the probability that a student arriving at the ATM will have to wait is equal to the utilization rate of the ATM.

The last can be calculated as:

$P_{n>0}=\rho=\dfrac{\lambda}{\mu}=\dfrac{1/3}{1/2}=\dfrac{2}{3}=0.67$

Then, the probability that a student arriving at the ATM will have to wait is 67%.

4 0

4 years ago