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Answer:
Width = 10 inches
Step-by-step explanation:
Given the perimeter of a rectangle of 68 inches, and a length that is 14 inches longer than its width.
We can establish the following values to help us solve for the width of a rectangle:
Perimeter (P) = 68 inches
Length (L) = 14 + W inches
Width (W) = unknown
<h3 /><h3><u>Solve for the Width (W)</u></h3>P = 2(L + W) ⇒ This is the same as P = 2L + 2W, except that 2 is factored out from the right-hand side.
Divide both sides by 2:
Substitute the value of the Perimeter and the length (L) into the formula:
Combine like terms on the right-hand side, and simplify the left-hand side of the equation:
Subtract 14 from both sides:
34 - 14 = 14 - 14 + 2W
20 = 2W
Divide both sides by 2 to solve for the width (W):
W = 10 inches
Therefore, the width of the rectangle is 10 inches.
<h3 /><h3><u>Double-check:</u></h3>Verify whether the derived value for the width is correct:
P = 2L + 2W
68 = 2(14 + 10) + 2(10)
68 = 2(34) + 20
68 = 48 + 20
68 = 68 (True statement).
Thus, the length of the rectangle is 34 inches, and the width is 10 inches.
The value of the given expression is
Solution:
Given expression is .
Let us first convert mixed fraction into improper fraction.
Substitute this in the given expression.
To simplify the above expression, 21 and 60 are cancelled by 3.
Do cross multiplication to make the denominator same.
The value of the given expression is