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Aleksandr [31]
3 years ago
9

What properties of carbon's abiliyu to form different large and complex structures ?

Chemistry
1 answer:
Bezzdna [24]3 years ago
6 0

Answer:

Catenation

Tetravalency

Explanation:

Catenation is the ability of carbon to forms covalent bonds with other carbon atoms and other elements to form longer chains and structures which is as a result of the presence of the vast number of organic compounds in nature.

Tetravalency property in carbon means it makes four bonds to other atoms. Carbon has four valence electrons, that is, four electrons in the outermost shell

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Calculate the approximate number of atoms in a bacterium, assuming the average mass of an atom is ten times the mass of a hydrog
mezya [45]

Answer: -

The approximate number of atoms in a bacterium is 10¹¹

Explanation: -

We are given the mass of a bacterium is 10⁻¹⁵ kg.

We are told that the mass of a hydrogen atom is 10⁻²⁷ kg.

Finally we learn that the average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.

Mass of an atom of bacterium = 10 x mass of hydrogen atom

                                                   = 10 x 10⁻²⁷ kg.

                                                   = 10⁻²⁶ kg.

Thus the number of atoms in a bacterium = \frac{Total mass}{mass of 1 bacterium atom}

                                                                      = \frac{10-15 kg}{10-26 kg}

                                                                      = 10¹¹


8 0
3 years ago
In the reaction
ivolga24 [154]
Water is the BL base if it accepted a proton from NH4.
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7 0
2 years ago
Which of the following is an example of a physical change?
o-na [289]

Answer:

I think b is the correct answer

7 0
3 years ago
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The reaction A + B → C has a ∆G'° of –20 kJ/mol at 25° C. Starting under standard conditions, one can predict that: A) at equili
Step2247 [10]

Answer:

C) at equilibrium, the concentration of C will be much greater than the concentration of A or B.  

Explanation:

A + B ⇌ C; ΔG° = -20 kJ·mol⁻¹

If ΔG is negative, the reaction is spontaneous and position of equilibrium lies to the right, so the equilibrium concentration of C is much greater than that of A or B.

A) is wrong. The molar ratio of A:B is 1:1. If their initial concentrations are 1 mol·L⁻¹, their final concentrations will be equal.

B) is wrong. The position of equilibrium lies to the right, so the concentration of C will be much greater than that of A.

D) and E) are wrong. ΔG says nothing about the rate of a reaction. It deals with the spontaneity and position of equilibrium not the speed at which equilibrium is achieved.

3 0
3 years ago
The normal boiling point of methanol is 64.7 ∘ C and the molar enthalpy of vaporization is 71.8kJ/mol . The value of ΔS when 1.3
guapka [62]

Answer:

286 J/K

Explanation:

The molar Gibbs free energy for the vaporization (ΔGvap) is:

ΔGvap = ΔHvap - T.ΔSvap

where,

ΔHvap: molar enthalpy of vaporization

T: absolute temperature

ΔSvap: molar entropy of the vaporization

When T = Tb = 64.7 °C = 337.9 K, the reaction is at equilibrium and ΔGvap = 0.

ΔHvap - Tb . ΔSvap = 0

ΔSvap = ΔHvap/Tb = (71.8 × 10³ J/K.mol)/ 337.9 K = 212 J/K.mol

When 1.35 mol of methanol vaporizes, the change in the entropy is:

1.35mol.\frac{212J}{K.mol} =286 J/K

7 0
3 years ago
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