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3 years ago

What properties of carbon's abiliyu to form different large and complex structures ?

Chemistry

1 answer:

Bezzdna [24]3 years ago

6 0

Answer:

Catenation

Tetravalency

Explanation:

Catenation is the ability of carbon to forms covalent bonds with other carbon atoms and other elements to form longer chains and structures which is as a result of the presence of the vast number of organic compounds in nature.

Tetravalency property in carbon means it makes four bonds to other atoms. Carbon has four valence electrons, that is, four electrons in the outermost shell

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7.26 of a hydrate, Cu(NO3)2.xH2O, formed 2.4 g copper(II) oxide.

goldfiish [28.3K]

Number of moles= mass/ molar mass

Or n=m/MM

n = number of moles

m = mass

MM = molar mass

1) n CuO = 2.4g / 79.54g/mol = 0.03 mol CuO

2) n Cu(NO3)2.xH2O = 7.26 g / 205.6 = 0.035 moles of Cu(NO3)2.xH2O

3) 205.6 g

Cu = 63.5 g

N = 14g

O =16g

H= 1 g

63.5+ (14+(16*3))*2+1*2+16 =205.6 g

4) yes is 188g

5) I don’t know, I assume was 1

6 0

4 years ago

Read 2 more answers

In the compound nh3, nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of ______________.

Digiron [165]

In the compound nh3, nitrogen has an oxidation number of 3+ and hydrogen has an oxidation number of -1
The molecule NH3 have a neutral charge so the number of oxidation number of it's component must be equal to zero. The molecule NH composed of 1 nitrogen and 3 hydrogens. If the nitrogen oxidation number is 3+, then hydrogen would be:

1* N + 3*H=0
1*+3 +3*H=0
3H= -3
H= -1

4 0

3 years ago

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_________ deficiency is the developing world’s most common cause of preventable brain damage.

aniked [119]

I believe the answer is A. Iron

7 0

3 years ago

The initial pressure of a mixture of C6H6 and an excess of H2 in a rigid vessel is 1.21 atm. A catalyst is introduced. After the

KengaRu [80]

Answer:

mole fraction of C6H6 = 0.613 atm

Explanation:

The equation for this reaction is :

$C_6H_6 _{(g)} + 3H_2_{(g)} \to C_6H_{12}_{(g)}$

Initial P₁ P₂ 0

Final 0 P₂ -P₁/2 P₁

After completion of the reaction;

P₁ + P₂ = 1.21 atm ----- (1)

P₂ - P₁/2 + P₁ = 0.839 atm

P₂ + P₁/2 = 0.839 atm ----- (2)

Subtracting (2) from (1); we have:

P₁/2 = 0.371

P₁ = 0.742 atm

From(1)

P₁ + P₂ = 1.21 atm

0.742 atm + P₂ = 1.21 atm

P₂ = 1.21 atm - 0.742 atm

P₂ = 0.468 atm

Thus, the partial pressure of C6H6 = 0.742 atm

∴

Partial pressure = Total pressure × mole fraction of C6H6

mole fraction of C6H6 = Partial pressure / Total pressure

mole fraction of C6H6 = 0.742 atm / 1.21 atm

mole fraction of C6H6 = 0.613 atm

5 0

3 years ago

Initially, a 55.0 liter compressible container, holding 2.4 moles of a gas, exerts a pressure of 760 millimeters of mercury at a

Bingel [31]

You would have to use the ideal gas law for this:
PV=nRT
Pressure, Volume, n=moles, R gas constant, Temperature in Kelvin
P=nRT/V
(1.8mol)(62.36)(309K)/43.0L = 805mm Hg

5 0

3 years ago

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