Answer: -
The approximate number of atoms in a bacterium is 10¹¹
Explanation: -
We are given the mass of a bacterium is 10⁻¹⁵ kg.
We are told that the mass of a hydrogen atom is 10⁻²⁷ kg.
Finally we learn that the average mass of an atom of the bacterium is ten times the mass of a hydrogen atom.
Mass of an atom of bacterium = 10 x mass of hydrogen atom
= 10 x 10⁻²⁷ kg.
= 10⁻²⁶ kg.
Thus the number of atoms in a bacterium = 
= 
= 10¹¹
Water is the BL base if it accepted a proton from NH4.
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Answer:
I think b is the correct answer
Answer:
C) at equilibrium, the concentration of C will be much greater than the concentration of A or B.
Explanation:
A + B ⇌ C; ΔG° = -20 kJ·mol⁻¹
If ΔG is negative, the reaction is spontaneous and position of equilibrium lies to the right, so the equilibrium concentration of C is much greater than that of A or B.
A) is wrong. The molar ratio of A:B is 1:1. If their initial concentrations are 1 mol·L⁻¹, their final concentrations will be equal.
B) is wrong. The position of equilibrium lies to the right, so the concentration of C will be much greater than that of A.
D) and E) are wrong. ΔG says nothing about the rate of a reaction. It deals with the spontaneity and position of equilibrium not the speed at which equilibrium is achieved.
Answer:
286 J/K
Explanation:
The molar Gibbs free energy for the vaporization (ΔGvap) is:
ΔGvap = ΔHvap - T.ΔSvap
where,
ΔHvap: molar enthalpy of vaporization
T: absolute temperature
ΔSvap: molar entropy of the vaporization
When T = Tb = 64.7 °C = 337.9 K, the reaction is at equilibrium and ΔGvap = 0.
ΔHvap - Tb . ΔSvap = 0
ΔSvap = ΔHvap/Tb = (71.8 × 10³ J/K.mol)/ 337.9 K = 212 J/K.mol
When 1.35 mol of methanol vaporizes, the change in the entropy is:
