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alexandr1967 [171]
3 years ago
10

Which notation is used to represent gamma decay?

Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
Gamma decay is a type of radioactivity in which an unstable atomic nucleus dissipates energy by gamma<span> emission, producing </span>gamma<span> rays. </span>gamma decay<span> in Science Expand. </span>gamma decay. A radioactive process in which an atomic nucleus loses energy by emitting a gamma<span> ray (a stream of high-energy photons).</span>
masya89 [10]3 years ago
7 0

<u>Answer:</u> The gamma decay is represented below.

<u>Explanation:</u>

Gamma decay is defined as the process in which an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and thus releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral.

The chemical equation representing gamma decay process follows:

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

where,

_Z^A\textrm{X}^* = unstable nuclei

_Z^A\textrm{X} = stable nuclei

_0^0\gamma = gamma particle

Hence, the gamma decay reaction is given below.

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What is the equation you use to determine the momentum of an object
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A certain radioactive isotope decays at a rate of 0.2​% annually. Determine the ​half-life of this​ isotope, to the nearest year
pychu [463]

Answer:

The half-life of the radioactive isotope is 346 years.

Explanation:

The decay rate of the isotope is modelled after the following first-order linear ordinary differential equation:

\frac{dm}{dt} = -\frac{m}{\tau}

Where:

m - Current isotope mass, measured in kilograms.

t - Time, measured in years.

\tau - Time constant, measured in years.

The solution of this differential equation is:

m(t) = m_{o}\cdot e^{-\frac{t}{\tau} }

Where m_{o} is the initial mass of the isotope. It is known that radioactive isotope decays at a yearly rate of 0.2 % annually, then, the following relationship is obtained:

\%e = \frac{m(t)-m(t+1)}{m(t)}\times 100\,\% = 0.2\,\%

1 - \frac{m(t+1)}{m(t)} = 0.002

1 - \frac{m_{o}\cdot e^{-\frac{t+1}{\tau} }}{m_{o}\cdot e^{-\frac{t}{\tau} }}=0.002

1 - e^{-\frac{1}{\tau} } = 0.002

e^{-\frac{1}{\tau} } = 0.998

-\frac{1}{\tau} = \ln 0.998

The time constant associated to the decay is:

\tau = -\frac{1}{\ln 0.998}

\tau \approx 499.500\,years

Finally, the half-life of the isotope as a function of time constant is given by the expression described below:

t_{1/2} = \tau \cdot \ln 2

If \tau \approx 499.500\,years, the half-life of the isotope is:

t_{1/2} = (499.500\,years)\cdot \ln 2

t_{1/2}\approx 346.227\,years

The half-life of the radioactive isotope is 346 years.

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Where are elements that form molecules of two of the same atoms commonly found on the periodic table?
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A 3-column table with 4 rows. The first column labeled Scenario has entries A, B, C, D. The second column labeled Object 1 has e
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Answer:

Scenario A: Toward object 1

Scenario B: Toward object 2

Scenario C: Toward object 1

Scenario D: Toward object 1

Explanation: I Just FInished the instruction on edjunueity, please consider giving me the branliest answer

Hope This Helps :)

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