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alexandr1967 [171]
3 years ago
10

Which notation is used to represent gamma decay?

Chemistry
2 answers:
natali 33 [55]3 years ago
7 0
Gamma decay is a type of radioactivity in which an unstable atomic nucleus dissipates energy by gamma<span> emission, producing </span>gamma<span> rays. </span>gamma decay<span> in Science Expand. </span>gamma decay. A radioactive process in which an atomic nucleus loses energy by emitting a gamma<span> ray (a stream of high-energy photons).</span>
masya89 [10]3 years ago
7 0

<u>Answer:</u> The gamma decay is represented below.

<u>Explanation:</u>

Gamma decay is defined as the process in which an unstable nuclei gives off excess energy by a spontaneous electromagnetic process and thus releases \gamma -radiations. These radiations does not carry any charge and are electrically neutral.

The chemical equation representing gamma decay process follows:

_Z^A\textrm{X}^*\rightarrow _Z^A\textrm{X}+_0^0\gamma

where,

_Z^A\textrm{X}^* = unstable nuclei

_Z^A\textrm{X} = stable nuclei

_0^0\gamma = gamma particle

Hence, the gamma decay reaction is given below.

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In this experiment you’ll be grabbing the relationship between mass and volume you’ll be placing the volume on the X axis and th
Contact [7]

The mass and volume has direct proportional to each other.

<h3>What is the relationship between mass and volume?</h3>

The volume of the object is directly proportional to its mass which means that if the volume increases the mass of the object increases also increase and vice versa. Due to this direct relationship, the line of regression will go straight between X and Y axis.

So we can conclude that mass and volume has direct proportional to each other.

Learn more about volume here: brainly.com/question/1972490

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6 0
2 years ago
At standard temperature and pressure. 0.500 mole of xenon gas occupies
ANEK [815]

Answer:

0.500 mole of Xe (g) occupies 11.2 L at STP.

General Formulas and Concepts:

<u>Gas Laws</u>

  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K

<u>Stoichiometry</u>

  • Mole ratio
  • Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

<em>Identify.</em>

0.500 mole Xe (g)

<u>Step 2: Convert</u>

  1. [DA] Set up:                                                                                                  \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)
  2. [DA] Evaluate:                                                                                               \displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}

Topic: AP Chemistry

Unit: Stoichiometry

3 0
2 years ago
Describe how replacing one light on a holiday string of bulbs with a "blinking" light would cause all the lights in the string t
stiks02 [169]

Answer: Chemical Reaction

Explanation:

6 0
3 years ago
Plz help i’m gonna cry i’m in class rn
iragen [17]

Answer:

if ur gonna cry then just dont cry its simple logic guyss!!!!!!!!!!!!

Explanation:

3 0
3 years ago
A bomb calorimetric experiment was run to determine the enthalpy of combustion of ethanol. The reaction is The bomb had a heat c
gulaghasi [49]

Answer:

The enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

Explanation:

The heat absorbed by the bomb and water is equal to the product of the heat  capacity and the temperature change. Working with this equation, and assuming no heat is lost to  the surroundings, we write :

qcal= Ccal × ΔT= 490 J/K × 276.7 K= <u>135,583 J</u> = 135.58 kJ

Note we expressed the temperature change in K, because the heat capacity is written in K.

<u> Now that we have the heat of combustion, we need to calculate the molar heat.  </u>

Because qsystem = qrxn + qcal and qrxn = -qcal, the heat change of the reaction is -135.58 kJ.

This is the heat released by the combustion of 4.40 g of ethanol ; therefore, we can write  the <u>conversion factor as 135.58 kJ/ 4.40 g</u>.

The molar mass of ethanol is 46.07 g, so the heat of combustion of 1 mole of ethanol is :

molar heat of combustion= -135.58 kJ/4.40 g x 46.07 g/ 1 mol= -1419.58 kJ/mol

Therefore, the enthalpy of combustion of ethanol in kJ/mol is -1419.58  kJ/mol.

3 0
3 years ago
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