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Lilit [14]
3 years ago
15

A mysterious white powder is found at a crime scene. A simple chemical analysis concludes that the powder is a mixture of sugar

and morphine (C17H19NO3), a weak base similar to ammonia. The crime lab takes 10.00 mg of the mysterious white powder, dissolves it in 100.00 mL water, and titrates it to the equivalence point with 2.84 mL of a standard 0.0100 M HCl solution. What is the percentage of morphine in the white powder?
a. 8.10%
b. 17.3%
c. 32.6%
d. 49.7%
e. 81.0%
Chemistry
1 answer:
iren [92.7K]3 years ago
6 0

Answer:

e. 81.0%

Explanation:

Morphine has Molar mass = 285.34 g/mol

Also, number of males of Morphine = Number of moles of HCl

(At equivalence point )

Now, number of moles of HCl = Molarity × volume

=0.01 mol × 2.84×10^(-3) L

= 2.84×10^(-5) mol

therefore number of moles of morphine= 2.85×10^(-5)

Mass of Morphine= No. of moles × molar mass

= 2.84×10^(-5)×285.34 g/mol

= 0.0081 g

= 8.1 mg

therefore

percentage of morphine = mass of morphine/ mass of powder×100%

= 8.1/10×100% = 81.0%

hence option e is correct.

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5 0
3 years ago
Calculate the enthalpy of the reaction
harkovskaia [24]

Answer : The enthalpy of the reaction is, -2552 kJ/mole

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given enthalpy of reaction is,

4B(s)+3O_2(g)\rightarrow 2B_2O_3(s)    \Delta H=?

The intermediate balanced chemical reactions are:

(1) B_2O_3(s)+3H_2O(g)\rightarrow 3O_2(g)+B_2H_6(g)     \Delta H_A=+2035kJ

(2) 2B(s)+3H_2(g)\rightarrow B_2H_6(g)    \Delta H_B=+36kJ

(3) H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)    \Delta H_C=-285kJ

(4) H_2O(l)\rightarrow H_2O(g)    \Delta H_D=+44kJ

Now we have to revere the reactions 1 and multiple by 2, revere the reactions 3, 4 and multiple by 2 and multiply the reaction 2 by 2 and then adding all the equations, we get :

(when we are reversing the reaction then the sign of the enthalpy change will be change.)

The expression for enthalpy of the reaction will be,

\Delta H=-2\times \Delta H_A+2\times \Delta H_B-6\times \Delta H_C-6\times \Delta H_D

\Delta H=-2(+2035kJ)+2(+36kJ)-6(-285kJ)-6(+44)

\Delta H=-2552kJ

Therefore, the enthalpy of the reaction is, -2552 kJ/mole

4 0
3 years ago
how many moles of ammonium chloride are required for a complete reaction with 420 mol of calcium hydroxide
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moles KOH = 26.5 g/56.1 g/mol=0.472  

moles K3PO4 = 0.472/3 =0.157

3 0
3 years ago
How many molecules are in 9.45 moles ? ( NaNO3)
Rzqust [24]

Answer:

There are 5.69*10²⁴ molecules in 9.45 moles.

Explanation:

The mole is defined as the amount of matter that particles have, that is, atoms and elementary entities.

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023*10²³ particles per mole and represents a quantity without an associated physical dimension. Avogadro's number applies to any substance.

Then the following rule of three can be applied: if 1 mole contains 6.023 * 10²³ molecules, 9.45 moles, how many molecules will it have?

amount of molecules=\frac{9.45 moles*6.023*10^{23}molecules }{1 mole}

Solving:

amount of molecules= 5.69*10²⁴⁴ molecules

<u><em>There are 5.69*10²⁴ molecules in 9.45 moles.</em></u>

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