Answer:
19.3 g/mL
Explanation:
The following data were obtained from the question:
Mass (m) = 12.4 kg
Volume (V) = 642 mL.
Density (D) =.?
Next, we shall convert 12.4 kg to grams. This can be obtained as follow:
1 kg = 1000 g
Therefore,
12.4 kg = 12.4 × 1000
12.4 kg = 12400 g
Therefore, 12.4 kg is equivalent to 12400 g.
Finally, we shall determine the density of the gold as follow:
Density is simply defined as the mass of the substance per unit volume of the substance. It can be represented mathematically as:
Density (D) = mass (m) / volume (V)
D = m/V
With the above formula, the density of gold can easily be obtained as follow:
Mass (m) = 12400 g
Volume (V) = 642 mL.
Density (D) =.?
D = m/V
D = 12400/642
D = 19.3 g/mL
Therefore, the density of hold is 19.3 g/mL
Answer:
Option D
Oxygen particles mix evenly with hydrogen particles.
Explanation:
Diffusion refers to the movement of gasses from a region of higher concentration to a region of lower concentration.
Diffusion occurs in gases because their particles are in a state of constant random motion.
Due to this continuous random motion, once the oxygen and the hydrogen are added to the container, they will begin to mix freely with each other until they fill up the entire volume of the container.
Answer:
69,632 grams
explanation
number of molecules =mass\molemass
nh3 14 +2×3=20
3.4×1024=m/20
cross multiply
grams =69,632
36inches in the air first bounce second bounce 15
The delocalized cloud of π electrons in benzene is formed by the overlap of 6<u> p-orbitals</u>.
So, option B is correct one.
In the case of hydrocarbons, delocalisation occurs in benzene rings , where a hexagon of six carbon atoms has decalized electrons spread over the whole ring.
All of the carbon atoms in the benzene rings are 
orbitals around the ring produces a framework of six sigma bonds, while the unhybridized p-orbitals which are perpendicular to this plane over in side-to-side fashion to form three pi-bonds.
To learn more about benzene
brainly.com/question/14525517
#SPJ4
