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Andreas93 [3]
3 years ago
15

Find the value of c that makes the expression a perfect square trinomial. x2 + 4x + c

Mathematics
1 answer:
masha68 [24]3 years ago
7 0

the value of c that makes the expression a perfect square binomial is c=4 .

<u>Step-by-step explanation:</u>

Here we have , an expression x2 + 4x + c or , x^2 + 4x + c . We need to find  the value of c that makes the expression a perfect square binomial. Let's find out:

We have ,  x^2 + 4x + c

⇒ x^2+4x+c

⇒ x^2+2(2)x+c

Now , we know that (a+b)^2=a^2+2(a)(b)+b^2

Comparing above equation  , to  x^2+2(2)x+c we get ;

⇒  x^2+2(2)x+c            { c=2^2  }

⇒  x^2+2(2)x+2^2

⇒  (x+2)^2

Therefore , the value of c that makes the expression a perfect square binomial is c=4 .

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Step-by-step explanation:

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y = 11.5

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6(6 + y) = 5(5 + 16)

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2 years ago
Latika reads half as many fiction books as she reads nonfiction.She reads three times as many nonfiction books as mystery novels
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She read 15 fiction books

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4 0
2 years ago
If the smallest angle of a triangle is 20° and it is included between sides of 4 and 7, then (to the nearest tenth) the smallest
lawyer [7]

Answer:

3.5

Step-by-step explanation:

The smallest side of a triangle is formed by the smallest angle in the triangle.

To find the side opposite (formed by) the 20 degree angle, we can use the Law of Cosines. The Law of Cosines states that for any triangle, c^2=a^2+b^2-ab\cos \gamma, where a, b, and c are the three sides of the triangle and \gamma is the angle opposite to c.

Let c be the side opposite to the 20 degree angle.

Assign variables:

  • a\implies 4
  • b\implies 7
  • \gamma \implies 20^{\circ}

Substituting these variables, we get:

c^2=4^2+7^2-2(4)(7)\cos 20^{\circ},\\c^2=16+49-56\cos 20^{\circ},\\c^2=12.377213236,\\c=\sqrt{12.377213236}=3.51812638147\approx \boxed{3.5}

Therefore, the shortest side of this triangle is 3.5.

5 0
3 years ago
Find the area of the shaded region .
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Calculate area of the white region inside circle.

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2 \cdot \frac{1}{2}(6)(6) = 36 ft^2

Area of the two white quarter circles in the bottom left and top right:

2 \cdot \frac{1}{4}\pi (6)^2 = 18\pi ft^2

Total area of unshaded white region inside circle:

(36 + 18\pi)ft^2

Area of entire circle including the white and shaded regions

\pi(6)^2 = 36\pi ft^2

Area of shaded region is area of entire circle - area of unshaded white region

36\pi - (36 + 18\pi) = (18\pi - 36) ft^2

7 0
2 years ago
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