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-Dominant- [34]
4 years ago
7

700%

Physics
1 answer:
aleksklad [387]4 years ago
4 0

Answer:

Approximately 22.9 seconds.

Explanation:

A sound wave travel 340m in 1 sec

For 7800m it will travel;

\frac{7800}{340} * 1 = 22.94117647 sec

It will take approximately 22.9 seconds.

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Which of the following would cause an iron bar to start generating a magnetic field? A Orienting the iron bar so that it points
shusha [124]

Answer:

Wrapping the bar with a coil of wire that has an electric current.

Explanation:

To cause an iron bar to start generating a magnetic field, wrap the bar with a coil that has an electric current.

  • This process is known as making magnetics using an electric current.
  • There is an interaction between electric and magnetic fields.
  • Electrical current can be induced by magnetic fields and magnetism can be induced by electric currents.

Wrapping the bar with a coil of wire that has electric current can cause an iron bar to start producing magnetic fields. This way, the iron bar becomes a magnet.

5 0
3 years ago
A motorcycle has a constant speed of 29.6 m/s as it passes over the top of a hill whose radius of curvature is 183 m. The mass o
coldgirl [10]

Answer:

a) centripetal force = m v^2 / R = 329 * (29.6 m/s)^2 / 183

F = 1580 Newtons

b) normal force = gravitational force - F = 329 * 9.8 - 1580 = 1640 N

8 0
3 years ago
an object with a mass of 70kilograms is supported at a height 8meters above the ground. what's the potential energy of the objec
ra1l [238]
Gravitational Potential Energy = mgh (m=mass; g=gravitational force(9.8N/kg); h = height)

Ug = (70kg)(9.8N/kg)(8m) = 5488J which is C.)
3 0
4 years ago
The dispersed particles of a colloid exhibit brownian motion, in which they move _____.
Archy [21]

The dispersed particles of a colloid exhibit brownian motion, in which they move _____. ... The dispersed particles of a colloid exhibit brownian motion, in which they move in a chaotic manner without a discernible pattern.

8 0
3 years ago
Read 2 more answers
One end of rod A is placed in a cold reservoir with a temperature of 5.00°C. The other end is held in a hot reservoir at 85.0°C.
slavikrds [6]

Answer:

1 / 2

Explanation:

This problem is a 1 - D steady state heat conduction with only one independent variable (x).

1 - D steady state:

Q = dT / Rc

Q = heat flow

dT = change in temperature between a pair of node

Rc = thermal resistance

Rc = L / k*A

Since in both cases Rod A and Rod B have identical boundary conditions:

dT_a = dT_b

So,

R_a =  L / k*(pi*r^2)

R_b = 2L / k*(pi*(2r)^2) = L / k*(2*pi*r^2)

Compute Q_a and Q_b:

Q_a = k * dT *(pi * r^2 * / L)

Q_a = k * dT*(2*pi * r^2 * / L)

Ratio of Q_a to Q_b

Q_a / Q_b = [k * dT *(pi * r^2 * / L)] / [k * dT*(2*pi * r^2 * / L)] = 1 / 2

5 0
3 years ago
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