Y-2x=6 => y=6+2x
Y+2x=0
(6+2x) + 2x = 0
6 + 4x = 0
4x= 6
X=6/4
X= 3/2
Y=6+2x
Y=6+2. 3/2
Y= 6 + 3
Y=9
Check: y-2x=6
9-2. 3/2 = 6
9 - 3 = 6
Given:
The equation is:

To find:
The graph of the line that contains ordered pairs that are solutions of the given equation.
Solution:
We need to find the graph of the given equation.
We have,

At
, we get


So, the x-intercept of the given equation is at point (0,4).
At
, we get


So, the y-intercept of the given equation is at point (4,0).
From the given graphs it is clear that the line in option C has x-intercept at point (0,4) and y-intercept at point (4,0).
Therefore, the correct option is C.
For this case, the first thing we must do is define a variable.
We have then:
x: real number
Now we write the expression:
-8 / (x + 3)
The number x can be all real different from minus three.
Answer:
-8 / (x + 3)
With x different from -3.
Answer: v = 1
1v + 6v = 7 Combine like terms
7v = 7 Divide both sides by 7
v = 1 Answer!
Answer: The quotient of 1,908÷ 36 is 53