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Doss [256]
2 years ago
5

What’s the area of the rectangle in terms of x if the length is (x+8) and the width is (2x-1)?

Mathematics
1 answer:
WARRIOR [948]2 years ago
5 0

Answer:

Step-by-step explanation:

A=LW\\ \\ A=(x+8)(2x-1)\\ \\ A=2x^2-x+16x-8\\ \\ A=2x^2+15x-8

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10.4% as a fraction is 104/1000
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Two hundred ninety three thousand eight hundred and five
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Simplify: Write your answer in scientific notation.<br> (3.3 x 10^7) + (7.7 x 10^8)
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The answer is 8.03x10^8
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A number, y, is equal to twice the sum of a smaller number and 3. The larger number is also equal to 5 more than 3 times the sma
Nata [24]

Answer:

The equations represent the situation is y=2x+6 and y=5+3x.

Step-by-step explanation:

Consider the provided information.

First convert the statement into mathematical representation.

Consider the smaller number is <em>x</em> and the larger number is <em>y</em>.

<em>y</em>, is equal to twice the sum of a smaller number and 3.    

This information can be written as: y=2(x+3)

Which can be further solve as:

y=2x+6

The larger number is also equal to 5 more than 3 times the smaller number.

This information can be written as: y=5+3x

Thus, the equations represent the situation is y=2x+6 and y=5+3x.

Which can be further solve as:

2x+6=5+3x

x=1

Now, substitute the value of <em>x</em> in y=5+3x.

y=5+3

y=8

3 0
3 years ago
Read 2 more answers
HELPP!!
SSSSS [86.1K]

Answer:

There are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

Step-by-step explanation:

This can be obtained by after a simple counting of number from 2020 and 2400 as follows:

The first set of integers are:

2345, 2346, 2347, 2348, and 2349.

Therefore, there are 6 integers in first set.

The second set of integers are:

2356, 2357, 2358, and 2359.

Therefore, there are 4 integers in second set.

The third set of integers are:

2367, 2368, and 2369.

Therefore, there are 3 integers in third set.

The fourth set of integers are:

2378, and 2379.

Therefore, there are 2 integers in fourth set.

The fifth and the last set of integer is:

2389

Therefore, there is only 1 integers in fifth set.

Adding all the integers from each of the set above, we have:

Total number of integers = 6 + 4 + 3 + 2 + 1 = 15

Therefore, there are 15 integers between 2020 and 2400 which have four distinct digits arranged in increasing order.

7 0
3 years ago
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