All you need to do is multiply 10 ft times 11, 12 ft times 8, and 6 ft times ten and then when you get all of the answers add them up and you have your answer
Answer:
Step-by-step explanation:
Lateral surface area of the triangular prism = Perimeter of the triangular base × Height
By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(34)² = (16)² + BC²
BC = 
= 
= 30 in.
Perimeter of the triangular base = AB + BC + AC
= 16 + 30 + 34
= 80 in
Lateral surface area = 80 × 22
= 1760 in²
Total Surface area = Lateral surface area + 2(Surface area of the triangular base)
Surface area of the triangular base = 
= 
= 240 in²
Total surface area = 1760 + 2(240)
= 1760 + 480
= 2240 in²
Volume = Area of the triangular base × Height
= 240 × 20
= 4800 in³
10 would be you best choice
The solution depends on the value of

. To make things simple, assume

. The homogeneous part of the equation is

and has characteristic equation

which admits the characteristic solution

.
For the solution to the nonhomogeneous equation, a reasonable guess for the particular solution might be

. Then

So you have


This means


and so the general solution would be
Answer:
- tn = 2097152 pennies
- tn = 20971.52 dollars.
Step-by-step explanation:
A surprisingly large amount of money.
The question is "Does the amount of money just double or do the previous amounts add to the present amount?"
I think it just doubles. Not only that, but she can't spend any of it until night 22 is reached.
- tn = a*2^(n - 1)
- a = 1 She starts with 1 penny.
- n = 22
- tn = 1*2^(22 - 1)
- tn = 1*2^21
- tn = 2097152 pennies
- tn = 20971.52 dollars.