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2 years ago

6. In right triangle ABC, mZC=3y-10,

Mathematics

1 answer:

lorasvet [3.4K]2 years ago

6 0

Answer:

scalene

Step-by-step explanation:

step 1

Find the value of y

we know that

The sum of the interior angles in a triangle must be equal to 180 degrees

In this problem

m∠A+m∠B+m∠C=180°

substitute the given values

$90\°+(y+40)\°+(3y-10)\°=180\°$

Solve for y

$4y+120=180$

$4y=180-120$

$4y=60$

$y=15$

step 2

Find the measure of angle B

m∠B=(y+40)°

substitute the value of y

m∠B=(15+40)=55°

step 3

Find the measure of angle C

m∠C=(3y-10)°

substitute the value of y

m∠C=(3(15)-10)=35°

The three interior angles are different

The three sides of the ABC triangle will also be different

therefore

The right triangle ABC is scalene

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Answer:

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2 years ago

Solve the right angle trig problem.

Lisa [10]

Answer:

x = 40.7057°

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Trigonometry

[Right Triangle Only] sin∅ = opposite over hypotenuse

Step-by-step explanation:

Step 1: Define

We have a right triangle. We can use trig to find the angle.

Step 2: Identify Variables

Angle = x

Opposite = 15

Hypotenuse = 23

Step 3: Find Angle x

Substitute: sinx° = 15/23
Inverse: x° = sin⁻¹(15/23)
Evaluate: x = 40.7057°

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2 years ago

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Steps:

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3 years ago

How many integers between 100 and 400 contain the digit 2?

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aalyn [17]

Answer:

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↑ we'll substitute this later (4th step onwards)

Differentiate the second time:

$3y^{2}.\frac{dy}{dx} + 3x^{2} = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} + 6x = 0 \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{dy}{dx})^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{-x^{2} }{y^{2} })^{2} = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + 6y(\frac{x^{4} }{y^{4} }) = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} + \frac{6x^{4} }{y^{3} } = - 6x \\\\3y^{2}.\frac{d^{2} y}{dx^{2}} = - 6x - \frac{6x^{4} }{y^{3} } \\\\$

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2 years ago