Given that there were 30 bacteria present originally.
a=30
Also given that the number doubles every one hour.
After one hour the count =2×30=60
Since the count doubles every hour it forms a G.P. with r=2
a,ar,ar2........
The count at the end of 2nd hour=ar^2=30×2^2=120
The count at the end of 4th hour=ar^4=30×2^4=480
The count at the end of 8th hour=ar^8n=30×2^8=7680
etc.
The count at the end of n^th hour=ar^n=30×2^n
Also, the equation y=30*(2)^8/1 give the same result y= 7680
(5k²)³
(5³)(k²)³
125k⁶
The answer is D.
Answer:
i think they are y and (x,y)
To start, first distribute 8 to (y+11) which would look something like this:
9y=8y+88
Now, subtract 8y from both sides in order to solve for and isolate the y value. This would result in your answer, y=88.
