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olga_2 [115]
3 years ago
11

Based on the following reaction, determine how much heat is released if 500. grams of methane is combusted in excess oxygen: CH4

+ 2 O2  CO2 + 2 H2O H= – 890 kJ
Chemistry
1 answer:
EastWind [94]3 years ago
3 0

Answer:

- 13,150.6kJ

Explanation:

CH4 + 2 O2 ------> CO2 + 2 H2O ΔH= – 890 kJ

The ΔH is enthalpy change of combustion , which is the heat is either absorbed or released by the combustion of one mole of a substance.

ΔH=−890 kJ/mol (released in the combustion of one mole of methane)

using the molar mass  (in grams )of methane to get moles of sample

(237g × 1 mole of CH4)/16.04g=14.776 moles  of CH4

Since 1 mole produces 890 kJ of heat upon combustion, then 14.776 moles will produce

ΔH = 14.776moles of CH4 × 890kJ/1mole of CH4

=13,150.6kJ

Therefore ΔH = - 13,150.6kJ

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The compound potassium carbonate, K_2 CO_3 is soluble in water. Write the formulas for the ions that interact with water as show
Rus_ich [418]

The compound potassium carbonate(K₂CO₃) is soluble in the water. The formulas for the ions that interact with the water is K⁺ and (CO₃)²⁻.

Dissociation of any compound is defined as the breaking of a compound into a simpler substance which is capable of recombining under different conditions. The compound potassium carbonate(K₂CO₃) is an ionic compound, and ionic compound is formed by a combination of cation and anion. When ionic compounds are dissolved in the water, it separates into the cations and anions.

Potassium carbonate(K₂CO₃) is a strong electrolyte. It means that it is completely dissociate in the water. Its dissociation in the water is shown as

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Therefore, the compound potassium carbonate forms K⁺ and (CO₃)²⁻ ions when interact with the water.

The question looks incomplete but the complete question is

The compound potassium carbonate is a strong electrolyte. Write the reaction when solid potassium carbonate is put into water

To know more about dissociation

brainly.com/question/19053344

#SPJ4

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