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nignag [31]
3 years ago
11

Explain how an increase or decrease in the permeability (i.e. opening or closing channels permeable) to K+, Na+, Ca2+, or Cl- wo

uld change the membrane potential from rest.
Physics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

An increase or decrease in the permeability of a cell membrane by opening or closing of ion channels would change the membrane potential of a cell membrane from resting membrane potential.

Explanation:

The Resting membrane potential (RMP) normally sits between -50 and -75. This RMP value depends upon the type of ion channels that are open and the concentration of different ions (K+, Na+, Ca2+, Cl-) in the intracellular and extracellular fluids.

For example, in a neuronal cell at a resting state Potassium (K) and Organic anions are found at a higher concentration within the cell than outside. Whereas, Sodium (Na) and Chloride (Cl-) ions are in higher concentration outside the cell. This difference in concentration provides a gradient for ions to flow down their concentration gradient when channels are open as a result of action potential. During depolarization, voltage gated Na+ ions open because of an electrical stimulus. As sodium ions rushes in the cell, the charge inside the cell raises from Negative to Positive changing the Resting Membrane Potential.

Once the cell has been depolarized , the voltage gated Na+ channels close. The raised positive charge inside the cell now causes K+ channels to open, potassium ions now move down the concentration gradient out of the cell so that membrane potential falls and starts to approach the Resting Membrane Potential. This is called re polarization.

So, that's how permeability or opening and closing of ion channels would change the Resting Membrane Potential (RMP).

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Chemical change , I think
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3 years ago
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A friend waves & yells at you. If the sound took 3.20 seconds to reach you and the speed of sound is 340 m/s,
xeze [42]

Answer:

1088 m

Explanation:

3.00 seconds times by 340 =1020+68=1088

5 0
3 years ago
A small economy car (low mass) and a limousine (high mass) are pushed from rest across a parking lot, equal distances with equal
Studentka2010 [4]

Answer:

The car that receives more kinetic energy is the small economy car.

Explanation:

K.E = 0.5*mv²

Where;

K.E is the kinetic Energy

M is the mass of an object

V is the velocity of the moving object

But F = m(v/t), from Newton's second law of motion

If equal forces were applied to the two cars, then the velocity of each car will be calculated as follows.

v = (Ft/m)

v² = (Ft/m)²

Substitute in the value of v² into Kinetic energy equation

K.E = 0.5*mv²

K.E = 0.5*m(Ft/m)² = (0.5*F²t²)/m

Also assuming equal distance, equal force and assuming equal time for both cars.

The above equation will reduce to, K.E = k/m

Where k = 0.5*F²t², which is equal in both cars.

Thus, Kinetic energy will depend only on the mass of each car.

From the above expression, Kinetic Energy received by each car is inversely proportional to the mass of the car.

A small economy car (low mass)  will receive more kinetic energy while a limousine (high mass) car will receive less kinetic energy.

Therefore, the car that receives more kinetic energy is the small economy car.

6 0
3 years ago
A train of mass 3.3 × 10^6 kg is moving at a constant speed up a slope inclined at an angle of 0.64°
AnnyKZ [126]

Answer:

C. 39 m/s

Explanation:

First we need to calculate the total force required to move the train along the inclined plane. So, it is clear that the work done will be equal to the component of the weight that is parallel to the inclined plane, because there is no frictional force present:

Force = F = mg Sin θ

where,

m = mass of train = 3.3 x 10⁶ kg

g = 9.8 m/s²

θ = Angle of Inclination = 0.64°

Therefore,

F = (3.3 x 10⁶ kg)(9.8 m/s²)Sin 0.64°

F = 3.612 x 10⁵ N

Now, the formula for power is:

P = FV

V = P/F

where,

V = Velocity of Train = ?

P = Power of Engine = 14 MW = 1.4 x 10⁷ W

Therefore,

V = 1.4 x 10⁷ W/3.612 x 10⁵ N

V = 38.75 m/s

which is approximately equal to:

<u>C. 39 m/s</u>

4 0
3 years ago
if a boat was moving at a velocity of 30 m/s to the south and it sailed for 30 minutes, what was the displacement of the boat?
kifflom [539]

If you move south at 30 m/s for 30 minutes, your displacement is

D = (30 mtr/s) x (30 min) x (60 sec/min)

D = (30 x 30 x 60) (mtr-min-sec/sec-min)

D =  54,000 meters south

D = <em>54 km south</em>

8 0
3 years ago
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