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nignag [31]
3 years ago
11

Explain how an increase or decrease in the permeability (i.e. opening or closing channels permeable) to K+, Na+, Ca2+, or Cl- wo

uld change the membrane potential from rest.
Physics
1 answer:
Fantom [35]3 years ago
8 0

Answer:

An increase or decrease in the permeability of a cell membrane by opening or closing of ion channels would change the membrane potential of a cell membrane from resting membrane potential.

Explanation:

The Resting membrane potential (RMP) normally sits between -50 and -75. This RMP value depends upon the type of ion channels that are open and the concentration of different ions (K+, Na+, Ca2+, Cl-) in the intracellular and extracellular fluids.

For example, in a neuronal cell at a resting state Potassium (K) and Organic anions are found at a higher concentration within the cell than outside. Whereas, Sodium (Na) and Chloride (Cl-) ions are in higher concentration outside the cell. This difference in concentration provides a gradient for ions to flow down their concentration gradient when channels are open as a result of action potential. During depolarization, voltage gated Na+ ions open because of an electrical stimulus. As sodium ions rushes in the cell, the charge inside the cell raises from Negative to Positive changing the Resting Membrane Potential.

Once the cell has been depolarized , the voltage gated Na+ channels close. The raised positive charge inside the cell now causes K+ channels to open, potassium ions now move down the concentration gradient out of the cell so that membrane potential falls and starts to approach the Resting Membrane Potential. This is called re polarization.

So, that's how permeability or opening and closing of ion channels would change the Resting Membrane Potential (RMP).

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Calculate the electric field strength at a point at which a test charge of 0.30 coulombs experiences a force of 5.0 newtons.
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The strength of electric field E is 17 N / C.

<u />

<u>Explanation:</u>

Electric field strength is defined as the force per unit charge acting at a point in the given field. The equation for the strength of the electric field is given by

                     E = F / q

where E represents the electric field strength,

           F represents the force in newton,

           q represents the charge in coulomb.

Given the charge q = 0.30 coulombs

                   force F = 5.0 N

Electric field strength E = force / charge

                                        = 5.0 / 0.30

                                    E  = 16.66 = 17 N / C.

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3 years ago
Chapter 16, Problem 63. A person is standing in a room at 18 ◦C. The exposed surface area and skin temperature of the person are
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Answer:Q=248.011 W

Explanation:

Given

Temperature of Room T_{\infty }=18^{\circ}\approx 291 K

Area of Person A=1.7 m^2

Temperature of skin T=32^{\circ}\approx 305 K

Heat transfer coefficient h=5 W/m^2.k

Emissivity of the skin and clothes \epsilon =0.9

\Delta T=32-18=14^{\circ}

Total rate of heat transfer=heat Transfer due to Radiation +heat transfer through convection

Heat transfer due radiation Q_1=\epsilon \sigma A(T^4-T_{\infty }^4 )

where \sigma =stefan-boltzman\ constant

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Q_1=129.01 W

Heat Transfer due to convection is given by

Q_2=hA(\Delta T)

Q_2=5\times 1.7\times 14=119 W

Q=Q_1+Q_2

Q=129.01+119=248.011 W

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