Answer:
The answer is 15000kgms^-2
Explanation:
Actually here we are using the formula F=ma
C., used in power plants I think.
In this problem, we apply the equation regarding kinematics expressed as vf^2 = v0^2 + 2as vf eventually becomes zero because the ball stops in the end. a = -9.8 m/s2s = 2 metres this time
This gives initial velocity, vo equal to 6.26m/s
now 6.26-(-8.85) = 15.11m/s
change in velocity/change in time = average acceleration 15.11/(12/1000) = 1259.167 m/s^2
Answer:
720 V
Explanation:
Given that,
The number of turns in primary coil, N₁ = 60
The number of turns in secondary coil, N₂ = 360
The input rms voltage, V₁ = 120 V
We need to find the output rms voltage of the secondary coil
. The relation between number of turns in primary coil - secondary coil to the input rms voltage to the output rms voltage is given by :

<h3>So, the output rms voltage of the secondary coil is 720 V. Hence, the correct option is (b).</h3>
Given:
P1 = 400 kPa
T1 = 110 K
T2 = 235K
Required:
P2
Solution:
Apply Gay-Lussac’s
law where P/T = constant
P1/T1 = P2/T2
P2 = T2P1/T1
P2 = (235K)(400kPa)
/ (110K)
P2 = 855 kPa