Y2 + x2 = 53
y − x = 5
y = 5 + x
(5+x)^2 + x^2 = 53
(5+x)(5+x) + x^2 = 53
25 + 10x + x^2 +x^2 = 53
2x^2 + 10x - 28 = 0
(x-2)(x+7)=0
x = 2 , x = - 7
y = 5 + 2
y = 7
y = 5 +(-7)
y = 5 - 7
y = - 2
I don't know for sure, but I think the answer is 200
Answer:
The mean for the combined sample = 6.
Step-by-step explanation:
We have been given that one sample of n = 10 scores has a mean of M = 8.
So the sum of 10 scores for 1st sample will be: 
We are also told that second sample of n = 5 scores has a mean of M = 2.
So the sum of 5 scores for 2nd sample will be: 
When the both samples are combined, so total points will be:
and total scores will be
.



Therefore, the mean for the combined sample will be 6.
Answer:
See attachment
Step-by-step explanation:
The given system is :


Let us equate both equations and solve for x.






The the two lines of this system will meet at (-4,9)
The graph is shown in the attachment.
Answer:
1.40 litres; order of operations
Step-by-step explanation:
Part A:
First, write it out in the full form.
#1 (.75 litres of blackberry juice + .60 litres of blueberry juice + .25 litres of guava juice) - .20 litres drank = 1.4 litres of juice remaining in the jar
Part B:
Removing the wordy descriptions from the expression, we get the following:
#2 (.75 + .60 +.25) - .20
or, by adding the numbers in the parentheses first:
#3 (1.60) - .20 = 1.40
#4 1.40 litres of juice left in the jar
The order of operations was used in moving from step #2 to step #3, as operations within the parentheses were conducted before subtracting the .20 litres of juice which were drank.