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3 years ago

What is the acceleration object velocity of +25m/s to rest in 5.0 s

Chemistry

1 answer:

Irina-Kira [14]3 years ago

4 0

The average acceleration is -5.0 m·s⁻².

The formula for acceleration (a) is

$a = \frac{v_{f}- v_{i}}{t}$

$v_{f}$ = 25 m·s⁻¹; $v_{i}$ = 0; $t$ = 5.0 s

∴ $a = \frac{0-25}{5.0}$ = -5.0 m·s⁻²

The negative sign tells you that the object is slowing down, i.e., it is decelerating.

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Match the term with its correct charge. Positive charge. Negative charge. Neutral: No electric charge. A. electron B. neutron C.

Roman55 [17]

negative charge is electron

positive charge is a proton

no charge is neutron

4 0

3 years ago

How many grams are there in 3.30x10 23 grams of n2i6

qwelly [4]

Technically, the answer should be 3.30 * 10^23 grams. But I think you mean either molecules, atoms, moles or grams of Ni2I6 with that number of molecules .

1 mole of Ni2 I6 = 6.02 * 10^23 molecules
x [mole] = 3.30 * 10^23 molecules

1/x = 6.02 * 10^23 / 3.30 * 10^23 Cancel the 10^23 on the right side
1/x = 6.02 / 3.30 Cross multiply
3.30 = 6.02 x Divide by 6.02
3.30 / 6.02 = x
x = 0.548 moles

what to do from here?

1 mole of Ni2I6 is
2 * Ni = 2 * 59 = 118 grams
6 * I = 6 * 131 = 786 grams
Total = 904 grams

Set up a proportion.
1 mole Ni2I6 = 904 grams
0.548 moles = x

1/0.548 = 904/x Cross multiply
x = 0.548 * 904
x = 495.4 grams of Ni2I6 <<<<<< Answer.

8 0

3 years ago

The oxidation of ammonia produces nitrogen and water via the following reaction: 4NH3(g) + 3O2(g) → 2N2(g) + 6H2O(l) Suppose the

Sonbull [250]

Answer:

The rate of consumption of $NH_{3}$ is 2.0 mol/L.s

Explanation:

Applying law of mass action to this reaction-

$-\frac{1}{4}\frac{\Delta [NH_{3}]}{\Delta t}=-\frac{1}{3}\frac{\Delta [O_{2}]}{\Delta t}=\frac{1}{2}\frac{\Delta [N_{2}]}{\Delta t}=\frac{1}{6}\frac{\Delta [H_{2}O]}{\Delta t}$

where $-\frac{\Delta [NH_{3}]}{\Delta t}$ represents rate of consumption of $NH_{3}$ , $-\frac{\Delta [O_{2}]}{\Delta t}$ represents rate of consumption of $O_{2}$ , $\frac{\Delta [N_{2}]}{\Delta t}$ represents rate of formation of $N_{2}$ and $\frac{\Delta [H_{2}O]}{\Delta t}$ represents rate of formation of $H_{2}O$ .

Here rate of formation of $H_{2}O$ is 3.0 mol/(L.s)

From the above equation we can write-

$-\frac{1}{4}\frac{\Delta [NH_{3}]}{\Delta t}=\frac{1}{6}\frac{\Delta [H_{2}O]}{\Delta t}$

Here $\frac{\Delta [H_{2}O]}{\Delta t}=3.0 mol/(L.s))$

So, $-\frac{\Delta [NH_{3}]}{\Delta t}=\frac{4}{6}\frac{\Delta [H_{2}O]}{\Delta t}$

Hence, $-\frac{\Delta [NH_{3}]}{\Delta t}=\frac{4}{6}\times 3.0 mol/(L.s)=2.0 mol/(L.s)$

6 0

3 years ago

Identify each charge of the subatomic particles ? Help me please ASAP

baherus [9]

Answer:

Particle: Charge:

Proton +1

Neutron 0

Electron -1

6 0

2 years ago

What are the uses of glycerin?

Ilia_Sergeevich [38]

Explanation:

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6 0

3 years ago