<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B5x%2B3%3D0" id="TexFormula1" title="2x^{2} +5x+3=0" alt="2x^{2} +5x+3=0" ali

3 years ago

gn="absmiddle" class="latex-formula">

1 answer:

8 0

Exact form: -3/7
Decimal form: -0.428581

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tamaranim1 [39]

You get everything you need from factoring the last expression:

$x^4-y^4=-176\sqrt7$

The left side is a difference of squares, and we get another difference of squares upon factoring. We end up with

$x^4-y^4=(x^2-y^2)(x^2+y^2)=(x-y)(x+y)(x^2+y^2)$

Plug in everything you know and solve for $x-y$ :

$-176\sqrt7=(x-y)\cdot4\cdot22\implies x-y=\boxed{-2\sqrt7}$

4 0

3 years ago

jeka94

Answer:

intersection point (-2,5)

Step-by-step explanation:

the line y = - 5 / 2 x you do the reciprocal which gets you x = -2 y = 5

5 0

3 years ago

Stella [2.4K]

Answer:

283

Step-by-step explanation:

4 0

2 years ago

In-s [12.5K]

You will get about 1300 a year

6 0

3 years ago

bearhunter [10]

Yes. For example x=-1 and y=-1/2

4 0

3 years ago