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Masja [62]
4 years ago
14

Please help! Will give Brainliest!

Mathematics
2 answers:
GREYUIT [131]4 years ago
8 0
What do you need help with?
And try taking a picture and posting it if you can't ask the question.
mr Goodwill [35]4 years ago
7 0
Sorry it is just easier for me to write than type I hope this helps if it is right lol good luck

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What is greater or less than
PIT_PIT [208]

Answer:

0.87 > 0.17

3.97 < 6.63

8.04 < 8.9

  Is that what ur looking for?

Step-by-step explanation:

6 0
4 years ago
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Please help me on this one! this is timed
e-lub [12.9K]
42 brotha you gotta cut down the data set until you reach the median
6 0
3 years ago
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True or false , help please lol
Ilya [14]

False

I think its false

8 0
3 years ago
Please someone help me to prove this. ​
morpeh [17]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Use the Double Angle Identity: sin 2Ф = 2sinФ · cosФ

Use the Sum/Difference Identities:

sin(α + β) = sinα · cosβ + cosα · sinβ

cos(α - β) = cosα · cosβ + sinα · sinβ

Use the Unit circle to evaluate: sin45 = cos45 = √2/2

Use the Double Angle Identities:   sin2Ф = 2sinФ · cosФ

Use the Pythagorean Identity: cos²Ф + sin²Ф = 1

<u />

<u>Proof LHS → RHS</u>

LHS:                                  2sin(45 + 2A) · cos(45 - 2A)

Sum/Difference: 2 (sin45·cos2A + cos45·sin2A) (cos45·cos2A + sin45·sin2A)

Unit Circle:    2[(√2/2)cos2A + (√2/2)sin2A][(√2/2)cos2A +(√2/2)·sin2A)]  

Expand:        2[(1/2)cos²2A  + cos2A·sin2A + (1/2)sin²2A]

Distribute:              cos²2A   + 2cos2A·sin2A + sin²2A  

Pythagorean Identity:    1 + 2cos2A·sin2A

Double Angle:                1 + sin4A

LHS = RHS:  1 + sin4A = 1 + sin4A   \checkmark

6 0
3 years ago
Based on what you know now, how are linear and exponential functions alike?
Ainat [17]

Answer:

They're similar in that they both have to maintain a steady rate of rise as they grow. While graphing, you can't adjust the slope or exponent after traveling up a graph.

Step-by-step explanation:

5 0
3 years ago
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