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soldi70 [24.7K]
3 years ago
7

What product(s) are expected in the ethoxide-promoted β-elimination reaction of 2-bromo-2,3-dimethylbutane? Omit ions, salts, an

d ethanol from your response.
Chemistry
1 answer:
Sidana [21]3 years ago
4 0
There are two possible products from this elimination: 
-2,3-dimethylbut-1-ene 
-2,3-dimethylbut-2-ene 

As the base is relatively unhindered, the reaction will form the Saytzeff product as the major product. The Saytzeff product is the most substituted alkene which is more stable due to hyperconjugation. In this reaction the Saytzeff product is 2,3-dimethylbut-2-ene.
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What I can do to conserve energy is always turning off the lights when I don’t need them, and not watching alot of Tv and go outside.
8 0
2 years ago
Metals posses varying reduction potentials. Iron can reduce Cu+2 (aq) to copper metal. Silver can reduce Au+ (aq) to gold metal.
natta225 [31]

<u>Answer:</u> The true statement is iron can reduce Au^+(aq) to gold metal

<u>Explanation:</u>

Single displacement reaction is defined as the reaction in which more reactive element displaces a less reactive element from its chemical reaction.

The reactivity of metal is determined by a series known as reactivity series. The metals lying above in the series are more reactive than the metals which lie below in the series.

A+BC\rightarrow AC+B

Metal A is more reactive than metal B.

We are given:

Iron can reduce copper, silver can reduce gold, sodium can reduce iron and copper can reduce silver metal.

The increasing order of reactivity thus follows:

Au

where, sodium is most reactive and gold is least reactive

For the given options:

<u>Option 1:</u>  Copper cannot easily reduce sodium ion to sodium metal because it is less reactive.

Cu(s)+Na^+(aq.)\rightarrow \text{ No reaction}

<u>Option 2:</u>  Iron cant easily reduce gold ion to gold metal because it is more reactive.

Fe(s)+3Au^+(aq.)\rightarrow Fe^{3+}(aq.)+3Au(s)

<u>Option 3:</u>  Silver cannot easily reduce iron ion to iron metal because it is less reactive.

Ag(s)+Fe^{3+}(aq.)\rightarrow \text{ No reaction}

Hence, the true statement is iron can reduce Au^+(aq) to gold metal

7 0
3 years ago
Explain the principle upon which separation is achieved in a distillation column.
aalyn [17]

Answer:

The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.

Explanation:

Distillation is a type of the separation process by physical means of a mixture on basis of its difference in boiling point or vapor pressure .  

Where we can just heat the mixture and separate out the components i.e the component with lower boiling point will form vapor easily and can be later condensed whereas the component with higher boiling point will remain as residue.

In case of a distillation column the same principle is applied at different stages to separate multiple components .The stages are known as trays or plates . In general , there is a certain liquid on each of the plate, and the arrangements are made for the ascending vapors to pass through the liquid and make contact with it . The fundamental principle involves the formation of equilibrium and separation into distillate and bottoms governed by the equilibrium composition curve , number of stages and the purity with which the distillate is required.

7 0
3 years ago
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Tpy6a [65]
A),b),c),d) answers?
4 0
3 years ago
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When optically active (R)-2-methylcyclohexanone is treated with either aqueous base or acid, racemization occurs. Explain.
IrinaK [193]

Answer:

See explanation

Explanation:

Racemization is said to occur when a 1:1 ratio of (+) and (-) enantiomers of a compound are produced in a reaction.

The reaction of optically active (R)-2-methylcyclohexanone with either aqueous base or acid leads to the formation of a planar enol species for reaction with acid and a planar enolate species for reaction with base.

Both reactions involves the formation of achiral species which reverts back to the chiral product with equal chances of the formation of both enantiomers of the product during the process. This leads to racemization of the product in both cases.

3 0
2 years ago
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