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2 years ago

What does x plus 5 - 2x plus 3y - y

Mathematics

1 answer:

Veseljchak [2.6K]2 years ago

4 0

5-2x+2y is the answer because if you add the (y) together that equals 2y and then you just keep the 5-2x together.

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If f(x) = 4x-9, evaluate f(3) <br>I need HELP ASAP!!!!!!!!!!!

seropon [69]

Answer:

substitute 3 as in x:

4(3)-9

= 12-9

= 3

Hope this helped - have a nice day & be safe

8 0

2 years ago

-7(k-8)+2k

Vladimir79 [104]

Step-by-step explanation:

-7(k-8)+2k Use distributive property.

-7k+56+2k Combine like terms.

-5k+56

Mother knows best :)

4 0

3 years ago

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

2 years ago

Find soluton to x^2-14x+49=25

Artyom0805 [142]

$\boxed{x=12 \ and \ x=2}$

<h2>Explanation:</h2>

In this exercise, we have the following equation:

$x^2-14x+49=25$

We can write this Quadratic Equation in Standard Form as follows:

$x^2-14x+49=25 \\ \\ Subtract \ 25 \ from \ both \ sides: \\ \\ x^2-14x+49-25=25-25 \\ \\ x^2-14x+24=0 \\ \\$

So this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

The sum is -14
The product is 24

Those numbers are:

-12 and -2
SUM: -12-2 = -14
PRODUCT: (-12)(-2)=24

So we can write this as:

$x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-12 \\ b=-2 \\ \\ x^2-14x+24=(x-12)(x-2)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=12 \ and \ x=2}$

<h2>Learn more:</h2>

Quadratic Ffrmua: brainly.com/question/10188317

#LearnWithBrainly

6 0

2 years ago

Find the sum of all 11 terms of an AP whose middlemost terms is 30?

Bond [772]

Let the difference between consecutive terms be D. If the middle term is 30, then the term before it is 30-D, and the term after it is 30+D. So the sum of these three terms would be (30-D) + 30 + (30+D) = 3*30.

Extending this sum to include all 11 terms centered around 30, we see that any addition of D is canceled by a balanced subtraction, leaving you with 11 copies of 30. So the value of the sum is 11*30 = 330.

6 0

2 years ago