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Trava [24]
3 years ago
11

$8050 invested for 5 years at 4.8% p.a

Mathematics
1 answer:
AURORKA [14]3 years ago
6 0

If my ans was helpful u can follow me.

You might be interested in
21) 0=-2y + 10 - 6x<br> 14 - 22y= 18x
zhenek [66]

Answer:

PlPlease be more spacific

Step-by-step explanation:

4 0
3 years ago
Please give the actual answer if you choose to anwser
zlopas [31]

9514 1404 393

Answer:

  C. 78°

Step-by-step explanation:

The sum of angles in a triangle is 180°.

  (7x-6)° +(4x+11)° +43° = 180°

  11x +48 = 180 . . . . . divide by °, simplify

  11x = 132 . . . . . . . subtract 48

  x = 12 . . . . . . . divide by 11

Then the measure of angle T is ...

  ∠T = (7x -6)° = (7(12) -6)°

  ∠T = 78°

6 0
3 years ago
Are 22 42 60 a right triangle or not?
Lelechka [254]

Answer:First things first, let's explain what a right triangle is. The definition is very simple and might even seem obvious for those who already know it: a right-angled triangle is a triangle where one and only one of the angles is exactly 90°. The other two angles will clearly be smaller than the right angle because the sum of all angles in a triangle is always 180°.

In a right angled triangle the sides are defined in a special way. The side opposing the right angle is always the biggest in the triangle and receives the name of "hypotenuse". The other two sides are called catheti. The relationship between the hypotenuse and each of the cathetus is a very simple one, as we will see when we will talk about Pythagoras' theorem.

Hypotenuse calculator

If all you want to calculate is the hypotenuse of a right triangle, this page and its right triangle calculator will work just fine. However, we would also recommend to use the specific tool we have developed at Omni Calculators: the hypotenuse calculator. The hypotenuse is opposite the right angle and can be solved by using the Pythagorean theorem. In a right triangle with cathetus a and b and with hypotenuse c, Pythagoras' theorem states that: a² + b² = c².

To solve for c, take the square root of both sides to get c = √(b²+a²). This extension of the Pythagorean theorem can be considered as a "hypotenuse formula". A Pythagorean theorem calculator is also an excellent tool for calculating the hypotenuse.

Let's now solve a practical example of what it would take to calculate the hypotenuse of a right triangle without using any calculators available at Omni:

Obtain the values of a and b,

Square a and b,

Sum up both values: a² + b²,

Take the square root of the result,

The square root will yield a positive and negative result. Since we are dealing with length, disregard the negative result,

The resulting value is the value of the hypotenuse c.

Now let's see what the process would be using one of Omni's calculator, for example, the right triangle calculator on this web page:

Insert the value of a and b into the calculator

Obtain the value of c immediately

As a bonus, you will get the value of the area for such a triangle.

Step-by-step explanation:Hope this helped u also may i have brainlist plz?

4 0
3 years ago
The height of a triangle is half the length of its base. The area of the triangle is 12.25cm. Find the height
pentagon [3]
Answer:  The height of the triangle is:  " 3.5 cm " .
_______________________________________________________
<u>
Note</u>:
 The formula/equation for the area, "A" , of a triangle is:

           A = (1/2) * b * h  ;  or write as:  A = (b * h) / 2 ; 
_________________________________________________
 in which:   "A = area of the triangle" ; 
                  "b = base length" ; 
                  "h = "[perpendicular] height" ; 
_________________________________________________
     Given:  h = (b/2) ;
                  A = 12.25 cm²
{Note:  Let us assume that the given area was "12.25 cm² " .}. 
_________________________________________________
 We are to find the height, "h" ; 

The formula for the Area, "A", is:   A = (b * h) / 2 ; 

Let us rearrange the formula ;
 to isolate the "h" (height) on one side of the equation; 

→ Multiply EACH side of the equation by "2" ; to eliminate the "fraction" ; 

2*A = [ (b * h) / 2 ] * 2 ; 

   to get:   " 2A = b * h " ; 

↔    " b * h = 2A " ; 

Divide EACH SIDE of the equation by "b" ; to isolate "h" on one side of the equation: 

        →  (b * h) / b  = (2A) / b ; 

to get: 
  
        →   h  =  2A / b ; 

Since  "h = b/2" ; subtitute "b/2" for "h" ; 
 
Plug in:  "12.25 cm² " for "A" ;

       →  b/2  =  2A/b ;   →  Note:  " 2A/b = [2* (12.25 cm²) ] / b " ;

Note:  " 2* (12.25 cm²) = 24.5 cm² ; 

Rewrite as: 

       →  b/2  =  (24.5 cm²) / b ;
_____________________________________
Cross-multiply:   b*b = (24.5 cm²) *2 ; 

to get:   b² = 49 cm² ; 

Take the "positive square root" of each side of the equation" ; 
            to isolate "b" on one side of the equation ; & to solve for "b" ; 

             →  +√(b²)  =  +√(49 cm²) ; 

             →  b = 7 cm ; 

Now, we want to solve for "h" (the height) :
_________________________________________________________
             →  h = b / 2 = 7 cm / 2 = 3.5 cm ; 
_________________________________________________________
Answer:  The height of the triangle is:  " 3.5 cm <span>" .
</span>_________________________________________________________
6 0
3 years ago
Solve for x. 5(x – 10) = 30 – 15x
SIZIF [17.4K]
Hey!


The first step to solving this problem would be to distribute the parenthesis. We do this so that we can get rid of the parenthesis.

<em>Original Equation :</em>
5 ( x - 10 ) = 30 - 15x

<em>New Equation {Changed by Distribution} :</em>
5x - 50 = 30 - 15x

The next step would be to 50 to both sides. The reason we do that is to get rid of the 50 that is on the left side of the equation.

<em>Old Equation :</em>
5x - 50 = 30 - 15x

<em>New Equation {Changed by Adding 50 to Both Sides} :</em>
5x = 80 - 15x

And now we would add 15x to both sides to get rid of the -15x on the right side of the equation.

<em>Old Equation :</em>
5x = 80 - 15x

<em>New Equation {Changed by Adding 15x to Both Sides} :</em>
20x = 80

Now we divide both sides by 20 to get x on it's own.

<em>Old Equation :</em>
20x = 80

<em>New Equation {Changed by Dividing Both Sides by 20} :</em>
\frac{20x}{20} = \frac{80}{20}

Finally, all we have to do is solve to find x.

<em>Old Equation :</em>
\frac{20x}{20} = \frac{80}{20}

<em>Solution {Old Equation Solved} :</em>
x = 4

<em>So, in the equation </em><span><em>5 ( x – 10 ) = 30 – 15x</em>,  x = 4.

Hope this helps!


- Lindsey Frazier ♥</span>
3 0
3 years ago
Read 2 more answers
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