a solution with a pH of 2.0 is strongly acidic
Answer:
2048.63 N
Explanation:
Force: The product of mass and the acceleration of a body. The S.I unit of Force is Newton(N).
From the question
P = F×V.................... Equation 1
Where P = power generated by the car, F = Total resistive force acting on the car, V = Velocity of the car.
make F the subject of the equation
F = P/V................ Equation 2
Given: P = 75.0 hp = (75×745.7) = 55927.5 W, V = 27.3 m/s
Substitute into equation 2
F = 55927.5/27.3
F = 2048.63 N
Hence the total resistive force acting on the car = 2048.63 N
Answer:
p2 = 9.8×10^4 Pa
Explanation:
Total pressure is constant and PT = P = 1/2×ρ×v^2
So p1 + 1/2×ρ×(v1)^2 = p2 + 1/2×ρ×(v2)^2
from continuity we have ρ×A1×v1 = ρ×A2×v2
v2 = v1×A1/A2
and
r2 = 2×r1
then:
A2 = 4×A1
so,
v2 = (v1)/4
then:
p2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v2)^2 = p1 + 1/2×ρ×(v1)^2 - 1/2×ρ×(v1/4)^2
p2 = 3.0×10^4 Pa + 1/2×(1000 kg/m^3)×(12m/s)^2 - 1/2×(1000kg/m^3)×(12^2/16)
= 9.75×10^4 Pa
= 9.8×10^4 Pa
Therefore, the pressure in the wider section is 9.8×10^4 Pa
The innermost electron of an atom has the lowest level of energy while the outermost electron has the highest level of energy.
There are different energy levels in the atoms of elements, for an atom to go into an higher level it has to obtain more energy and to go to lower level it has to lose energy.<span />
Answer:
El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.
Explanation:
Para determinar la velocidad del perro con respecto al observador sentado desde la playa a través del concepto de velocidad relativa, descrito en la siguiente fórmula:
(1)
Donde:
- Velocidad del perro relativo al barco, en kilómetros por hora.
- Velocidad del perro con respecto al observador, en kilómetros por hora.
- Velocidad del barco con respecto al observador, en kilómetros por hora.
Si sabemos que
y
, entonces la velocidad del perro con respecto al observador es:



El observador verá correr al perro sobre la cubierta del barco a una velocidad de 40 kilómetros por hora.