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Lubov Fominskaja [6]
3 years ago
12

What is the value of x in the equation -6x = 5x+ 22? -22 0 -2 02 O 22

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0

Answer:

x = -2

Step-by-step explanation:

Solve  -6x = 5x + 22

add 6x to both sides

0 = 6x + 5x + 22

0 = 11x + 22

11x = -22

x = -22/11

x = -2

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Darina [25.2K]

Step-by-step explanation:

4y

4 (5)

4×5

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3 0
3 years ago
What is the value of <img src="https://tex.z-dn.net/?f=%20a_%7B1%7D%20" id="TexFormula1" title=" a_{1} " alt=" a_{1} " align="ab
julia-pushkina [17]
The correct awnser is a or c i hope i helped
8 0
3 years ago
Please help. Thank you​
love history [14]

Answer:

The length of side x is x = \sqrt{6}

Step-by-step explanation:

Pythagorean Theorem:

In a right triangle, with sides a and b, and hypothenuse h, we have that:

a^2 + b^2 = h^2

In this question:

The vertical line on the sides means that both are equal, that is, measuring x, so a = b = x.

Hypothenuse is the square root of 12. So h = \sqrt{12}

x^2 + x^2 = (\sqrt{12})^2

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x^2 = 6

x = \sqrt{6}

The length of side x is x = \sqrt{6}

8 0
2 years ago
Jacob consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Jacob's body
sasho [114]

Answer: 0.87400mg of caffeine.

Step-by-step explanation:

You have

N(t)=N0(e^−rt)(1)

as a general Exponential decay equation where N0 is the amount at t=0, N(t) is the amount remaining at time t and r is the exponential decay constant. You're specifically given that after 10 hours, the decay factor is 0.2601, i.e.,

N(10)/N(0)=N0(e^−10r)/N0(e^0)= e^−10r=0.2601 . .(2)

Taking the last 2 parts of (2) to the power of 0.1t gives

e^−rt=0.2601^.1t . .(3)

This means that

N(t)=N0(e^−rt)=N0(0.2601^.1t). .(4)

Also,

N(2.56)N(1.56)=N0(0.2601.1(2.56))N0(0.2601.1(1.56))=0.2601.1(2.56−1.56)=0.2601^.1

= 0.87400mg of caffeine.

6 0
3 years ago
Factor completely: 12a^2b–18ab^2–30ab^3
Goryan [66]

Answer:

6ab(2a-3b-5b²)

Step-by-step explanation:

6(2a²b-3ab²-5ab³)

6a(2ab-3b²-5b³)

6ab(2a-3b-5b²)

7 0
3 years ago
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