I think the answer is B. Because if you multiply 6x8 it’s 48 divided by 2 equals 24
Answer:
Explanation:
String str = "Broccoli is delicious.";
String[] Secondstr = str.split(" ");
System.out.println("second word is " + Secondstr[1]);
<u>Hi dear user! </u>
<u>Hope my answer helps you and solve your queries. </u>
First of all,
ISP which is an acronym of Internet Service Provider, keeps the track of all the activities their users perform through their network.
For eg :-
You have a connection of Airtel, whatever you will access through your Airtel network will always be tracked by your ISP which is Airtel. If you delete your search/download history from your phone/laptop, still it can be seen by Airtel, you cannot delete from there end. Even if you access anything in incognito mode, then your browser does not stores your data but your ISP still can see what all you accessed in incognito mode.
Now coming to your next question,
If you delete your data from your phone or laptop, it is still somewhere saved in the hard drive of that device. The file is deleted from the device but it's hard drive still have that file, and anyone can access to that data by using a certain software but for that, the person will also need your hard drive. There are certain softwares like Disk Drill which is used to recover the hard drive's data.
Hope your queries are resolved !
Answer:
Description: Write a MASM 32bit program with a loop and indexed addressing that calculates the sum of all thegaps between successive array elements. The array elements are doublewords, sequenced in nondecreasing order.
;Include Irvine32.inc file used with link library for 32 bit applications
.386
.model flat,stdcall
.stack 4096
ExitProcess proto,dwExitCode:dword
INCLUDE Irvine32.inc
.data
myArray DWORD 0,2,5,9,10
arrSize = ($-myArray)/TYPE myArray
gapArr DWORD arrSize-1 DUP(?)
sum DWORD ?
.code
main PROC
;Call the procedure
call Clrscr
;Initialize ESI pointer
mov esi, 0
mov ecx, arrSize
dec ecx
L1:
mov eax, myArray[esi+4]
sub eax, myArray[esi]
mov gapArr[esi], eax
inc esi
loop L1
;Calculate the sum of gaps between array elements
mov sum, 0
mov esi, 0
mov ecx, arrSize
dec ecx
; move gapArr[esi] to a temporary register and then add that register value to sum
L2:
mov edx, gapArr[esi]
add sum, edx
inc esi
loop L2
INVOKE ExitProcess,0
main ENDP
END main
Explanation:
