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ale4655 [162]
3 years ago
11

A survey of 1,000 men and women asked, "Do you earn over $50,000 per year?" The table below shows the responses for males and fe

males:
Male Female Total
Income over $50,000 485 385 870
Income below $50,000 65 65 130
Total 550 450 1,000


Based on these data, are "being male" and "earning over $50,000" independent events?


A) Yes, P(being male | the person earns over $50,000) ≠ P(being male)
B) Yes, P(being male | the person earns over $50,000) = P(being male)
C) No, P(being male | the person earns over $50,000) ≠ P(being male)
D) No, P(being male | the person earns over $50,000) = P(being male)

Will give a "Brainliest answer" to the first person to respond
Mathematics
2 answers:
frutty [35]3 years ago
7 0
                                               Male    Female    Total
Income over $50,000         485        385         870
Income below $50,000        65           65        130
<span>Total                                       550        450       1,000

Probability of being male: 550/1000 = 0.55
Probability of earning over $50,000: 870/1000 = 0.87

0.55 x 0.87 = 0.4785

Probability of being male and earning over $50,000: 485/550 = 0.8818

</span><span>C) No, P(being male | the person earns over $50,000) ≠ P(being male)</span><span>


</span>
pentagon [3]3 years ago
3 0

I agree with the answer below/above

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alexgriva [62]

Answer:

0.25

Step-by-step explanation:

11/12 = 0.917

2/3 = 0.667

0.917 - 0.667 = 0.25

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As a first step in solving the system shown, Yumiko multiplies both sides of the equation 2x – 3y = 12 by 6. By what factor shou
GenaCL600 [577]

Answer:

Yumiko should multiply the other equation by 3.

If she adds the two equations she would be left with the variable 'x'.

Step-by-step explanation:

Given the two equations are as follows:

$ 2x - 3y = 12 \hspace{5mm} \hdots (1) $

$ 5x + 6y = 18 \hspace{5mm} \hdots (2) $

It is given that she multiplies the first equation by 6. Therefore, (1) becomes

$ 12x - 18y = 72 \hspace{15mm} \hdots (a) $

Now, note that the sign of the variable 'y' is negative. So, if we make the co-effecient of 'y' equal in both the cases, add them it would result in the elimination of the variable 'y'.

The co-effecient of y in Equation (2) is 6. To make it 18 like it is in Equation (1), we multiply throughout by 3.

Therefore, Equation (2) becomes:

$ 15x + 18y = 54 \hspace{5mm} \hdots (b) $

Now, we add Equation (a) and Equation (b).

$ \implies 12x - 18y + 15x + 18y = 72 + 54 $

$ \implies 27x = 126 $

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Equation: 27x = 126

7 0
3 years ago
Number 15 please help
OverLord2011 [107]
I would believe its 10
4 0
3 years ago
Plz guys help i need asap<br> its part b im stuck
aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

  • 1st quarter-2
  • 2nd quarter-9
  • 3rd quarter-7
  • 4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4

Hence, there are 4 more home goals than away goals.

4 0
3 years ago
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