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fiasKO [112]
3 years ago
9

An entity should consider the cost of a control in relationship to the risk. Which of the following controls best reflects this

philosophy for a large dollar investment in heavy machine tools?
A. Placing security guards at every entrance 24 hours a day.
B. Having all dispositions approved by the vice president of sales.
C. Conducting a weekly physical inventory.
D. Imprinting a controlled identification number on each tool.
Business
1 answer:
lozanna [386]3 years ago
5 0
The answer is D. Your are welcome
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The organization primarily responsible for establishing accounting and reporting standards in the United States is the Financial
Triss [41]

Answer:

This statement is True.

Explanation:

The Financial Accounting Standards Board (FASB) is the successor of the <u><em>Accounting Principles Board</em></u> and was founded in 1973. Currently based in Norwalk - Conn, the FASB is responsible of establishing the Generally Accepted Accounting Principles (GAAP), and, overall, is in charge of setting accounting and financial reporting standards for public and private companies, as well as non-profit organizations in the United States. The FASB is also currently working to establish worldwide acceptable standards together with the International Accounting Standards Board (IASB).

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3 years ago
The mission statement of your business should contain all of the following elements except the
Zarrin [17]
C. expected profit margins
the mission statement provides information about the company as to who, why and how they plan to operate
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3 years ago
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Cullumber Manufacturing Company purchased 14600 switches to make 6300 units. The standard allows for 2 switches per unit. The co
earnstyle [38]

Answer:

d. $1,875 unfavorable

Explanation:

Direct material quantity variance is computed as;

= (AQ - SQ) × SP

AQ = Actual quantity = 6,300 units

SQ = Standard quantity = 14,200 / 2 = 7,300 units

SP = Standard price = $0.80

Direct material quantity variance

= (6,300 - 7,300) × 0.80

= -1,000 × $0.80

= -1,875 unfavorable

3 0
3 years ago
Can someone help me please? I Attached the question.<br> THANKS!!
Rasek [7]

Answer:

The absolute reference is $D$2

The relative reference is A2

The Mixed reference is  $D2

Explanation:

The absolute reference is  identify when $ fixes the cell row and colum

The relative reference is that any colum or row can be altered and there is nothing fixed with $

The Mixed reference is  identify when $ either the cell row or colum

4 0
3 years ago
A body in the solar system has a period of 10,759.22 days and a perihelion speed of 10.18 km/s. a. Calculate the aphelion radius
anastassius [24]

Answer:

Explanation:

From the information given, by applying Kepler's 3rd law,

T^2 \alpha  a^3

where;

T = period

a = semi major axis

T = 356 days (for earth)

a = 1 AU = 1.496 \times 10^8 \ km

Therefore, T^2 = ca^3

c= \dfrac{365^2}{(1.496 \times 10^8)^3}

c = 3.9791 \times 10^{20} \ day^2/km^3

However, if the body in the solar system has a period of 10.759.22 days, then, a =?

∴

T^2 = ca^3

a3 = \dfrac{10759.22^2}{3.9791 \times 10^{-20}}

a^3 = 2.9092 \times 10^{27}

a= \sqrt[3]{2.9092 \times 10^{27}}

a = 1.4275 \times 10^9 \ km

However, the velocity for a perihelion = 10.18 km/s

Using the formula

v = \sqrt{GM ( \dfrac{2}{r}-\dfrac{1}{a})} to calculate the radius, we have:

G = 6.674 \times 10^{-11}

M = 1.989\times 10^{30} \ kg

r = perihelion

v ^2= GM ( \dfrac{2}{r}-\dfrac{1}{a})

(10.18 \times 10^3) ^2= 6.674 \times 10^{-11} \times 1.989 \times 10^{30}  ( \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}})

7.8068 \times 10^{-13}= \dfrac{2}{r}-\dfrac{1}{1.425 \times 10^{12}}

\dfrac{2}{r} = 1.4824 \times 10^{-12}

r = \dfrac{2}{1.4824 \times 10^{-12}}

r = 1.349 \times 10^{12}

Similarly, the perihelion is expressed by the equation,

r = a(1 - e)

where ;

e= eccentricity

∴

1.349 \times 10^{12} = 1.425 \times 10^{12} ( 1 - e)

1.349 \times 10^{12}  -  1.425 \times 10^{12}= -  1.425 \times 10^{12} (e)

-7.6\times 10^{10}= -  1.425 \times 10^{12} (e)

\dfrac{-7.6\times 10^{10}}{-  1.425 \times 10^{12}}=  (e)

e ( eccentricity) = 0.0533

Aphelion radius in natural miles, r = a( 1+ e)

r = 1.425 \times 10^{12} ( 1 + 0.0533)

r = 1.50 \times 10^{12} \ m

to nautical miles, we have:

r = 1.50 \times 10^{12} \times 0.00054  \ nautical \ mile

radius of aphelion \mathbf{r = 8.10 \times 10^8} nautical miles

In respect to the value of a( i.e 1.4275 \times  10^9 \ km)

the body of the solar system is Saturn

5 0
3 years ago
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