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kobusy [5.1K]
3 years ago
11

If a stronger solution of sodium bicarbonate was used in beaker B, would it require more or less acetic acid to neutralize and w

hy? If a weaker solution of sodium bicarbonate was used i
Chemistry
1 answer:
Dmitriy789 [7]3 years ago
3 0

Answer:

A stronger acid is needed to neutralize the reaction.

Explanation:

Neutral pH solutions are because the acid counteracts the effect of the base, and vice versa.

Both chemical products, both acid and base, reach a pH of 7, which indicates the neutrality of the solution in the reaction, that is, the solution is neither acidic nor basic but NEUTRAL.

The higher the alkalinity of the base, the greater the acidity of the acid will be needed to balance and balance the pH to give neutrality as the final product.

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Approximately how long does it take for the moon's phases to change from a NEW moon to a FULL moon?
stiks02 [169]

Answer:

4 weeks

Explanation:

It takes 4 weeks for the cyclle to be happening again

8 0
3 years ago
In Part III, the phenolphthalein indicator is used to monitor the equilibrium shifts of the ammonia/ammonium ion system. The phe
AnnZ [28]

The pink color in the solution fades. Some of the colored indicator ion converts to the colorless indicator molecule.

<h3>Explanation</h3>

What's the initial color of the solution?

\text{NH}_4\text{Cl} is a salt soluble in water. \text{NH}_4\text{Cl} dissociates into ions completely when dissolved.

\text{NH}_4\text{Cl} \; (aq)\to {\text{NH}_4}^{+} \; (aq) +{\text{Cl}}^{-} \; (aq).

The first test tube used to contain \text{NH}_4\text{OH}. \text{NH}_4\text{OH} is a weak base that dissociates partially in water.

\text{NH}_4\text{OH} \; (aq) \rightleftharpoons {\text{NH}_4}^{+}  \;(aq)+ {\text{OH}}^{-} \; (aq).

There's also an equilibrium between \text{OH}^{-} and {\text{H}_3\text{O}}^{+} ions.

{\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l).

\text{OH}^{-} ions from \text{NH}_4\text{OH} will shift the equilibrium between \text{OH}^{-} and {\text{H}_3\text{O}}^{+} to the right and reduce the amount of {\text{H}_3\text{O}}^{+} in the solution.

The indicator equilibrium will shift to the right to produce more {\text{H}_3\text{O}}^{+} ions along with the colored indicator ions. The solution will show a pink color.

What's the color of the solution after adding NH₄Cl?

Adding \text{NH}_4\text{Cl} will add to the concentration of {\text{NH}_4}^{+} ions in the solution. Some of the {\text{NH}_4}^{+} ions will combine with \text{OH}^{-} ions to produce \text{NH}_4\text{OH}.

The equilibrium between  \text{OH}^{-} and {\text{H}_3\text{O}}^{+} ions will shift to the left to produce more of both ions.

{\text{OH}}^{-}\;(aq) + {\text{H}_3\text{O}}^{+} \;(aq) \to 2\; \text{H}_2\text{O} \;(l)

The indicator equilibrium will shift to the left as the concentration of {\text{H}_3\text{O}}^{+} increases. There will be less colored ions and more colorless molecules in the test tube. The pink color will fade.

7 0
4 years ago
Give the number of significant figures: 369,132,000 sec
Yuliya22 [10]
The number of significant figures in 369,132,000 is 6

3 0
3 years ago
Read 2 more answers
What is the molarity of a solution that contains 0.082 mol KI in a 2.03 L solution?
astraxan [27]

Answer:

molarity of the KI solution = 0.04 mol/L

Explanation:

Molarity (M) is the concentration of a solution expressed as the number of moles of solute per liter of solution.  

The law that we can applied to calculate the M is:  

M = n / V

n - number of moles

V- volume of the solution (liters)

Then insert in the equation the values from the question;  

M = 0.082 mol  /  2.03 L = 0.04 mol/L

4 0
3 years ago
Which redox reaction would most likely occur if zinc and copper metal were
sweet-ann [11.9K]

Answer:

C

Explanation:

b/c when copper and zinc metal are addedto solution,then the solution will be consider under redox reaction

5 0
3 years ago
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