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GrogVix [38]
3 years ago
9

When atomic orbitals of two nuclei overlap, the mutual attraction between a negatively charged electron pair and the two positiv

ely charged nuclei forms:
(A) a covalent bond
(B) an ionic bond
(C) an orbital bond
(D) none of the above
Chemistry
1 answer:
Lera25 [3.4K]3 years ago
6 0

Answer: Option (A) is the correct answer.

Explanation:

It is known that when sharing of electrons take place between two combining atoms then the bond formed is known as a covalent bond. In general, a covalent bond is formed between two non-metal atoms.

For example, the compound HCl has a covalent bond between the hydrogen and chlorine atom. As hydrogen atom has 1 valence electron and chlorine atom has 7 valence electrons.

So, in order to attain stability both these atoms will share their valence electrons and hence, a covalent bond is formed.

On the other hand, when an electron is transferred from one atom to another then it tends to form an ionic bond.

For example, the compound NaCl has an ionic bond.

Thus, we can conclude that when atomic orbitals of two nuclei overlap, the mutual attraction between a negatively charged electron pair and the two positively charged nuclei forms a covalent bond.

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What is the freezing point of an aqueous 1.58 molal nacl solution?
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How many kilograms of solvent would contain 0.43 mol of CaO in a 2.5 molality solution
dalvyx [7]
<h3>Answer:</h3>

0.024 kg CaO

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Aqueous Solutions</u>

  • Molarity = moles of solute / liters of solution

<u>Atomic Structure</u>

  • Reading a Periodic Tables
  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

0.41 mol CaO

2.5 M Solution

<u>Step 2: Identify Conversions</u>

1000 g = 1 kg

Molar Mass of Ca - 40.08 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of CaO - 40.08 + 16.00 = 56.08 g/mol

<u>Step 3: Convert</u>

  1. Set up:                                \displaystyle 0.43 \ mol \ CaO(\frac{56.08 \ g \ Cao}{1 \ mol \ CaO})(\frac{1 \ kg \ CaO}{1000 \ g \ CaO})
  2. Multiply:                              \displaystyle 0.024114 \ kg \ CaO

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 2 sig figs as our lowest.</em>

0.024114 kg CaO ≈ 0.024 kg CaO

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3 years ago
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