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2 years ago

Which of the following liquids has the highest viscosity

2 answers:

8 0

I’m pretty sure that the answer is between oil or honey, but I think that its honey because its between 2,000 and 10,000 more than water.

Answer: D. honey?

storchak [24]2 years ago

4 0

Answer:

honey has the highest viscosity

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Starting at atmospheric pressure, by how much must the pressure change in order to lower the boiling point of water by 1° C? You

Marina86 [1]

Answer:

ΔP = -3556.36 Pa

Explanation:

Atmospheric pressure, P = 101300 Pa

Latent heat of boiling water, $L_{B} = 2.256 * 10^{6} J/kg$

Boiling point at atmospheric pressure, T = 373.15 K

ΔT = 1 K

The change in volume as the water boils to vapor will be

$\triangle V = V_{v} - V_{l}$

Since the volume of vapor ( $V_{v}$ ) is far greater than the volume of liquid ( $V_{l}$ )

$\triangle V = V_{v}$

Using the ideal gas equation:

$PV_{v} = RT\\V_{v} = RT/P$

R = 8.314 J/mol-K

$V_{v} = \frac{8.314 * 373.15}{101300} \\V_{v} = 0.0306 m^{3}$

ΔV = 0.0306 m³

Molecular weight of water, MW = 0.018 kg/mol

Using the Clausius - Clapeyron equation:

$\triangle P = \frac{L_B \triangle T}{T \triangle V}* MW\\\triangle P = \frac{2.256 * 10^{6} *1}{373.15* 0.0306}* 0.018$

ΔP = -3556.36 Pa

But the pressure change is said to lower the boiling point of water, only a negative pressure change will lower the boiling point.

ΔP = 3556.36 Pa

4 0

3 years ago

Where are the most massive elements found on the periodic table?

iragen [17]

By atomic radius, the bottom left

5 0

3 years ago

Read 2 more answers

An atom is found in group 17 and contains 10 neutrons. How many valence

Naddika [18.5K]

Just 7 electrons this is the answer

8 0

3 years ago

If you have 10.0 g of hydrogen and 5.0 g of oxygen, what mass of the excess reagent remains after the completion of the reaction

mario62 [17]

mass Hydrogen=9.376 g

<h3>Further explanation </h3>

Reaction

2H₂+O₂⇒2H₂O

mass H₂ = 10 g

mol H₂(MW=2 g/mol) :

10 : 2 = 5

mass O₂=5 g

mol O₂(MW=32 g/mol) :

5 : 32 = 0.156

O₂ limiting reactant

mol H₂: mol O₂ = 2: 1, so mol H₂ :

2 x 0.156 = 0.312

mol H₂ :

5 - 0.132 =4.688

mass of H₂ :

4.688 x 2 =9.376 g

<h3 />

7 0

3 years ago

How many moles are in 17.31 g of NaHCO,?

dimulka [17.4K]

Answer:

0.33moles

Explanation:

RAM of;

Na = 23, H=1, C=12, O=16

molar mass of NaHCO= 23+1+12+16= 52g/mol

mole= mass / molar mass

mole = 17.31/52

mole= 0.33moles

7 0

3 years ago