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Vitek1552 [10]
3 years ago
9

This table gives a few (x,y) pairs of a line in the coordinate plane.

Mathematics
2 answers:
Anna11 [10]3 years ago
4 0

Answer:0,4

I hope this helps, all i did was put the table into a website that made it into a equation then put that equation into desmos and it showed the y intercept of the line.

nlexa [21]3 years ago
3 0

Answer:

The answer would be (0,4)

Step-by-step explanation:

I haven't done this in a while! Hopefully I got it right :)

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Can all quadrilaterals be inscribed in a circle? Explain
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Depends of the size of the quadrilateral in relation to the circle, but otherwise, yes
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Please help ASAP. I am confused
Lesechka [4]

Answer:

So if ∠X is 70° then ∠Y is most likely going to be 70° as well. So if you take 180° which is a straight line and subtract both of the 70°'s you'd get 40°. This answer seems pretty accurate to me.

Step-by-step explanation:

Hope this helps you out! :)

(If any question s put them below and I'll try my best to answer them)

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3 years ago
6. Determine how each multiplication or
tangare [24]
A) 27, 81
b) -30,-15
c) -3, 1
d) -320, 1280
3 0
3 years ago
Point C is twice as close to point B as it is to point A. If point A is at -30 and point B is at 30, what are two possible value
arsen [322]

different between A and B

=30-(-30)

=60

position of C from A or B

=(60÷3)×2

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possible value of c

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8 0
3 years ago
Read 2 more answers
Given that 1 x2 dx 0 = 1 3 , use this fact and the properties of integrals to evaluate 1 (4 − 6x2) dx. 0
Debora [2.8K]

So, the definite integral  \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Given that

\int\limits^1_0 {x^{2} } \, dx = 13

We find

\int\limits^1_0 {(4 - 6x^{2} )} \, dx

<h3>Definite integrals </h3>

Definite integrals are integral values that are obtained by integrating a function between two values.

So, Integral \int\limits^1_0 {(4 - 6x^{2} )} \, dx

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx = \int\limits^1_0 {4} \, dx - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - \int\limits^1_0 {6x^{2} } \, dx \\=  4[x]^{1}_{0}    - 6\int\limits^1_0 {x^{2} } \, dx \\= 4[1 - 0]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4[1]    - 6\int\limits^1_0 {x^{2} } \, dx\\= 4    - 6\int\limits^1_0 {x^{2} } \, dx

Since

\int\limits^1_0 {x^{2} } \, dx = 13,

Substituting this into the equation the equation, we have

\int\limits^1_0 {(4 - 6x^{2} )} \, dx = 4 - 6\int\limits^1_0 {x^{2} } \, dx\\= 4 - 6 X 13 \\= 4 - 78\\= -74

So, \int\limits^1_0 {(4 - 6x^{2} )} \, dx= - 74

Learn more about definite integrals here:

brainly.com/question/17074932

4 0
2 years ago
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