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astra-53 [7]
3 years ago
10

I need help answering these Significant Figures - precise measurements questions

Chemistry
1 answer:
jok3333 [9.3K]3 years ago
7 0

Answer:

3.0  x {10}^{4}

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Attachment, what are chromosomes?​
anyanavicka [17]

Explanation:

chromosomes is a threadlike structure of nucleic acid and protein found in the nucleus of most living cells carrying genetic information in the form of genes.

4 0
3 years ago
In a(n) _____ contract, the powerful party dictates the terms of the agreement and eliminates the other party’s free will.
Lesechka [4]
I honestly think it would be a victor contract.. 


6 0
3 years ago
Pls help :)
prisoha [69]

Answer:

0.484 mole

Explanation:

1 mole of glucose reacts with 6 moles of O2, producing :

6 moles of CO2

6 moles of H2O

678 kcal

Using rule of three you have:

1 mole of glucose -> 678 kcal

x mole of glucose -> 328 kcal

x = 328/678 * 1 =0.484 mole

6 0
4 years ago
The question is below
rodikova [14]
The anode is the electrode where the oxidation occurs.

Cathode is the electrode where the reducction occurs.

Equations:

  Mn(2+) + 2e-  --->  Mn(s)                      Eo = - 1.18 V
2Fe(3+) + 2e-  ----> 2 Fe(2+)                2Eo = + 1.54 V

The electrons flow from the electrode with the lower Eo to the electrode with the higher Eo yielding to a positive voltage.

Eo = 1.54 V - (- 1.18) = 1.54 + 1.18 = 2.72

Answer: 2.72 V

3 0
3 years ago
Give the following reaction: ammonium nitrate—> dinitrogen monoxide + water.
Vladimir [108]

Answer:

a) NH₄NO₃ ⇒ N₂O + 2 H₂O

b) 1.69 × 10²³ molecules

Explanation:

Step 1: Write the balanced equation

NH₄NO₃ ⇒ N₂O + 2 H₂O

Step 2: Convert 11.2 g of NH₄NO₃ to moles

The molar mass of NH₄NO₃ is 80.04 g/mol.

11.2 g × 1 mol/80.04 g = 0.140 mol

Step 3: Calculate the moles of H₂O produced

0.140 mol NH₄NO₃ × 2 mol H₂O/1 mol NH₄NO₃ = 0.280 mol H₂O

Step 4: Calculate the number of molecules in 0.280 moles of water

We will use Avogadro's number.

0.280 mol × 6.02 × 10²³ molecules/1 mol = 1.69 × 10²³ molecules

6 0
3 years ago
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