From x = 1.0 m to x = 4.25 m, displacement = 3.25 m
Average velocity of crawling of baby = 0.226 m/s
We know that time taken = Displacement/Time
=
= 14.38 seconds
So, the baby will take a time of 14.38 seconds from x=1.0m to x=4.25m at an average velocity of 0.226 m/s.
Answer:
0.356 times the mass pass through equilibrium per second.
Explanation:
Given that,
Spring constant = 10 N/m
Mass = 2 kg
Stretched spring = 2m
We need to calculate the frequency
Using formula of frequency
Where, m = mass
k = spring constant
Put the value into the formula
We know that,
Hertz = cycle per second
Hence, 0.356 times the mass pass through equilibrium per second.
this question is centered around newtons second law f=ma
First you need to find the acceleration
that gives you 0.36 recurring(on both numbers) m/s²
mass= force ÷ acceleration
mass= 85.25 kg
if you want to check
f=ma
85.25 × 0.36 recurring (remember its on both numbers not just 6) = 31 N