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3 years ago

A tension of 35.0N is applied downward on a 2.50kg mass. What is the acceleration of the mass?

Physics

2 answers:

Bess [88]3 years ago

7 0

Answer:

$\text{B. }-14.0\:\mathrm{m/s^2}$

Explanation:

From Newton's 2nd Law, we have $\Sigma F=ma$ .

Substituting given values, we get:

$-35.0=2.50a,\\a=\frac{-35.0}{2.50},\\a=\boxed{-14.0\:\mathrm{m/s^2}}$

*Note the negative sign simply implies that the mass is travelling downwards (direction).

Assoli18 [71]3 years ago

3 0

Answer:

D. -23.8 m/s2

Explanation:

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3 years ago

as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies. true or false?

GenaCL600 [577]

Answer:

False

Explanation:

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Therefore , as the trait is dominant and controlled by a single gene,the mutation must have occurred on both diploid copies is a false statement.

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3 years ago

What is the net force needed to accelerate a 21.4 kg grocery sack upward at 1.5 m/s2?

marshall27 [118]

Answer:

32.1 N Please Give Brainliest

Explanation:

force = mass x acceleration

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2 years ago

An astronaut is standing on the surface of a planetary satellite that has a radius of 1.74 × 10^6 m and a mass of 7.35 × 10^22 k

ExtremeBDS [4]

Answer:

2.87 km/s

Explanation:

radius of planet, R = 1.74 x 10^6 m

Mass of planet, M = 7.35 x 10^22 kg

height, h = 2.55 x 10^6 m

G = 6.67 x 106-11 Nm^2/kg^2

Use teh formula for acceleration due to gravity

$g=\frac{GM}{R^{2}}$

$g=\frac{6.67\times 10^{-11}\times 7.35\times 10^{22}}{1.74^{2}\times 10^{12}}$

g = 1.62 m/s^2

initial velocity, u = ?, h = 2.55 x 10^6 m , final velocity, v = 0

Use third equation of motion

$v^{2}=u^{2}-2gh$

0 = v² - 2 x 1.62 x 2.55 x 10^6

v² = 8262000

v = 2874.37 m/s

v = 2.87 km/s

Thus, the initial speed should be 2.87 km/s.

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3 years ago

What is the half life-life of your 100 atoms of Carbon-14?

Naddika [18.5K]

Answer:

Answer: It takes 5,730 years for half the carbon-14 to change to nitrogen; this is the half-life of carbon-14. After another 5,730 years only one-quarter of the original carbon-14 will remain

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2 years ago