Answer:
Momentum of bullet
momentum of baseball
Explanation:
As we know that momentum is defined as the product of mass and velocity
here we know that
mass of the bullet = 8 gram
velocity of bullet = 340 m/s
momentum of the bullet is given as
Now we have
mass of baseball = 0.2 kg
velocity of baseball = 40 m/s[/tex]
momentum of baseball is given as
Answer:
0.12 mm ; 140.50 rad/m ; 628.32 rad/sec ; +
Explanation:
Given the wave equation of the form :
y(x, t) = ym sin(kx ± ωt)
Mas per unit length (u) = 5 g/cm = (5÷1000)kg / 0.01m) = 0.005kg/0.01m = 0.5kg/m
Tension, T = 10 N
Amplitude, A = 0.12 mm
Frequency, F = 100 Hz
Comparing with the general wave equation :
y = Asin(kx ± ωt)
A = amplitude = ym = 0.12 mm
2.) k = 2π / λ
Recall :
v = fλ
v = sqrt(T/u) = sqrt(10/0.5) = sqrt(20) = 4.472
λ = v/ f = 4.472 / 100 = 0.04472
Hence,
k = (2 * π) / 0.04472
k = 140.50 rad/m
3.) Angular frequency, ω
ω = 2πf = 2 * 3.14 * 100 = 628.32 rad/sec
4.) sign is +ve
Direction of wave propagation as given is in the negative x axis
Testing the electrical resistance of different materials. it is the answer
Answer: Air resistance and/or drag.
Explanation: The parachute adds drag to the parachutist, thus making him fall slower and safely to the ground.
