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4 years ago

What does classify mean

2 answers:

7 0

Clas·si·fyˈklasəˌfī/verbarrange (a group of people or things) in classes or categories according to shared qualities or characteristics."mountain peaks are classified according to their shape"assign (someone or something) to a particular class or category."elements are usually classified as metals or nonmetals"synonyms:categorize, group, grade, rank, rate, order, organize, range, sort, type, codify, bracket, systematize, systemize; Moredesignate (documents or information) as officially secret or to which only authorized people may have access."government officials classified 6.3 million documents in 1992"

love history [14]4 years ago

4 0

Put it in a category. A group of something with similar characteristics.

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How many infrared photons of frequency 2.57 x 1013 Hz would need to be absorbed simultaneously by a tightly bound molecule to br

victus00 [196]

Answer:

Explanation:

f = 2.57 x 10^13 Hz

E = 10 eV = 10 x 1.6 x 10^-19 J = 1.6 x 10^-18 J

Energy of each photon = h f

Where, h is Plank's constant

Energy of each photon = 6.63 x 10^-34 x 2.57 x 10^13 = 1.7 x 10^-20 J

Number of photons = Total energy / energy of one photon

N = (1.6 x 10^-18) / (1.7 x 10^-20) = 94.11 = 94

6 0

3 years ago

Consider a household that uses 14,000 kWh of electricity and 900 gal of fuel oil, per year, during a heating season. The average

MissTica

Answer:

reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

Explanation:

given data

electricity consume = 14000 kWh

fuel consume = 900 gal

CO₂ produced of fuel = 26.4 lbm/gal

CO₂ produced of electricity = 1.54 lbm/kWh

oil and electricity usage = 21 percent

to find out

the reduction in the amount of CO₂ emissions

solution

we calculate the amount of CO₂ produce here that is

amount of CO₂ produce = ( electricity consume×CO₂ produce electricity + fuel consume × CO₂ consume fuel ) ........................1

put here value

amount of CO₂ produce = ( 14000 × 1.54 + 900 × 26.4 )

amount of CO₂ produce = 45320 lbm/yr

we know reduction is 21%

reduction in amount of CO₂ produced is

reduction in CO₂ produced = 45320 × 21%

reduction in CO₂ produced = 9517.2 lbm per year

so reduction in the amount of CO₂ emissions by that household per year is 9517.2 lbm per year

3 0

3 years ago

Jimmy is cooking pasta in a pot of water on the stove. He uses a stopwatch to see how long the pasta takes to cook depending on

Alex787 [66]

Answer:

stove

Explanation:

The stove is the independent variable in this question as it does not depend on anything like other variables such as pot, water, temperature and of cause pasta.

The pot depends on the stove, the water depends on the pot and stove, the pasta depends on the water and its temperature.

Cheers.

4 0

3 years ago

a coil has n turns enclosing an area of a. in a physics laboratory experiment, the coil is rotated during the time interval δt f

Mrac [35]

The correct answer for the question that is being presented above is this one:

Phi = BAsin(theta)
1. Phi(i) = BA 
2. Phi(f) = 0 
3. EMF = N(phi(i)-phi(f))/deltat

Here are the follow-up questions:

1. What is the total magnitude Phi_initial of the magnetic flux through the coil before it is rotated? 
2. What is the magnitude Phi_final of the total magnetic flux through the coil after it is rotated? 
3. What is the magnitude of the average emf induced in the coil?

8 0

3 years ago

Suppose the Sun appeared to you 900 times dimmer than it does now. How far away from the Sun would you be? (A) 1/9 AU (B) 3 AU

Harrizon [31]

Answer:

The correct answer is option 'c': 30 AUs

Explanation:

For a spherical wave front emitted by sun with total energy 'E' the energy density over the surface when it is at a distance 'r' from the sun is given by

$e=\frac{E}{4\pi r^{2}}$

This energy per unit area is sensed by observer as intensity of the sun.

Let the initial intensity of sun at a distance $r_{1}$ be $e_{1}$

Thus if the sun becomes 900 times dimmer we have

$e'=\frac{e_{1}}{900}\\\\\frac{E}{4\pi r_{2}^{2}}=\frac{1}{900}\times \frac{E}{4\pi r_{1}^{2}}\\\\\Rightarrow r_{2}^{2}={r_{1}^{2}}\times 900\\\\\therefore r_{2}={r_{1}}\times {30}$

Thus the distance increases 30 times.

5 0

3 years ago