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3 years ago

14

What does classify mean

2 answers:

Alexxx [7]3 years ago

7 0

Clas·si·fy<span>ˈklasəˌfī/</span>verbarrange (a group of people or things) in classes or categories according to shared qualities or characteristics."mountain peaks are classified according to their shape"<span>assign (someone or something) to a particular class or category."elements are usually classified as metals or nonmetals"<span>synonyms:<span>categorize, group, grade, rank, rate, order, organize, range, sort, type, codify, bracket, systematize, systemize; <span>More</span></span></span>designate (documents or information) as officially secret or to which only authorized people may have access."government officials classified 6.3 million documents in 1992"</span>

love history [14]3 years ago

4 0

Put it in a category. A group of something with similar characteristics.

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Beers of snakes thunderstorms darkness in water are classified as blank phobias

Scrat [10]

I believe all of these would be known as specific phobias.

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2 years ago

Which one of the following statements concerning superconductors is false? A constant current can be maintained in a superconduc

julsineya [31]

Answer:

All materials are superconducting at temperatures near absolute zero kelvin.

Explanation:

All materials are superconducting at temperatures near absolute zero kelvin is false concerning superconductors.

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2 years ago

During a solar eclipse, which of the following is true?

kaheart [24]

Answer:

The Moon blocks the suns light from hitting the surface of the earth

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2 years ago

Read 2 more answers

A 1300 kg car traveling at 35 mph rear-ends a 1000 kg car traveling 25 mph. Just after the collision (but before the driver’s sl

guajiro [1.7K]

Answer

given,

before collision

mass of car A = m_a = 1300 kg

velocity of car A = v_a = 35 mph

mass of car B = m_b= 1000 kg

velocity of car B = v_b = 25 mph

after collision

V_a = 30 mph

V_b = 31.5 mph

Initial momentum

$P_1 = m_av_a + m_b v_b$

$P_1 = 1300 \times 35+ 1000 \times 25$

$P_1 =70500 Kg.m/s$

final momentum

$P_2 = m_aV_a + m_b V_b$

$P_2 = 1300 \times 30+ 1000 \times 31.5$

$P_2 =70500 Kg.m/s$

here initial momentum is equal to the final momentum of the car.

hence, momentum is conserved in the collision.

6 0

2 years ago

A 1430 kg is moving at 25.6 m/s when a force is applied, in the direction of the cars motion. The car speeds up to 31.3 m/s. If

vladimir1956 [14]

The car accelerates with magnitude <em>a</em> such that

31.3 m/s = 25.6 m/s + <em>a</em> (5.4 s)

→ <em>a</em> = (31.3 m/s - 25.6 m/s) / (5.4 s) ≈ 1.056 m/s²

Then the applied force has a magnitude <em>F</em> of

<em>F</em> = (1430 kg) <em>a</em> ≈ 1500 N

3 0

2 years ago