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lukranit [14]
3 years ago
5

Can u solve both 20. and 22. Geometry

Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
8 0

Hey there!!

(1) Both the angles sum up to be 180.

(2) Both the angles sum up to be 90

_________________

(1) 4x+5+8x-5=180

... 12x=180

... x= 180/12

... x = 15

________________

(2) 4z+3z+6=90

... 7z+6=90

... 7z=84

... z=84/7

... x=12

__________________

Hope it helps!


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100-point Question!!!
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Answer:

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g(x)

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And many more.

The approach or formula to use depends on the question.

In this case, the combined function is:

f(x) = 75+ 10xf(x)=75+10x

The savings function is given as

s(x) = 85s(x)=85

The allowance function is given as:

a(x) = 10(x - 1)a(x)=10(x−1)

The new function that combined his savings and his allowances is calculated as:

f(x) = s(x) + a(x)f(x)=s(x)+a(x)

Substitute values for s(x) and a(x)

f(x) = 85 + 10(x - 1)f(x)=85+10(x−1)

Open bracket

f(x) = 85 + 10x - 10f(x)=85+10x−10

Collect like terms

mark as brainiest

f(x) = 85 - 10+ 10xf(x)=85−10+10x

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4 0
2 years ago
If 2tanA=3tanB then prove that,<br>tan(A+B)= 5sin2B/5cos2B-1​
Fed [463]

By definition of tangent,

tan(A + B) = sin(A + B) / cos(A + B)

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sin(x + y) = sin(x) cos(y) + cos(x) sin(y)

cos(x + y) = cos(x) cos(y) - sin(x) sin(y)

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tan(A + B) = (sin(A) cos(B) + cos(A) sin(B)) / (cos(A) cos(B) - sin(A) sin(B))

Multiplying the right side by 1/(cos(A) cos(B)) uniformly gives

tan(A + B) = (tan(A) + tan(B)) / (1 - tan(A) tan(B))

Since 2 tan(A) = 3 tan(B), it follows that

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… = 5 tan(B) / (2 - 3 tan²(B))

Putting everything back in terms of sin and cos gives

tan(A + B) = (5 sin(B)/cos(B)) / (2 - 3 sin²(B)/cos²(B))

Multiplying uniformly by cos²(B) gives

tan(A + B) = 5 sin(B) cos(B) / (2 cos²(B) - 3 sin²(B))

Recall the double angle identities for sin and cos:

sin(2x) = 2 sin(x) cos(x)

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and multiplying uniformly by 2, we find that

tan(A + B) = 10 sin(B) cos(B) / (4 cos²(B) - 6 sin²(B))

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The Pythagorean identity,

cos²(x) + sin²(x) = 1

lets us rewrite the double angle identity for cos as

cos(2x) = 1 - 2 sin²(x)

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… = 5 sin(2B) / (4 cos(2B) + cos(2B) - 1)

… = 5 sin(2B) / (4 cos(2B) - 1)

as required.

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stich3 [128]

Answer:

  see below

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