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lukranit [14]
4 years ago
5

Can u solve both 20. and 22. Geometry

Mathematics
1 answer:
SCORPION-xisa [38]4 years ago
8 0

Hey there!!

(1) Both the angles sum up to be 180.

(2) Both the angles sum up to be 90

_________________

(1) 4x+5+8x-5=180

... 12x=180

... x= 180/12

... x = 15

________________

(2) 4z+3z+6=90

... 7z+6=90

... 7z=84

... z=84/7

... x=12

__________________

Hope it helps!


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Svetradugi [14.3K]

Answer:

La razón de niñas a niños en la guardería es de 2 niñas por cada 3 niños.

Step-by-step explanation:

Una razón es una división entre dos números, generalmente en forma racional (fraccionaria). La razón de niñas a niños en la guardería es la cantidad de niñas dividida por la cantidad de niños de la dicha guardería, Es decir:

x = \frac{20}{30}

x = \frac{2}{3}

La razón de niñas a niños en la guardería es de 2 niñas por cada 3 niños.

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6 0
2 years ago
Read 2 more answers
Angie and Becky each completed a separate proof to show that the measures of vertical angles AKG and HKB are equal. Who complete
Ann [662]

Answer:

Becky completed the proof incorrectly.

Step-by-step explanation:

The only difference of the two proofs, at least what I can see, is the reason for step 2. Angie claims that it is the Definition of Supplementary Angles, while Becky claims Angle Addition Postulate.

The Definition of Supplementary Angles states that m∠A + m∠B = 180°.

While the Angle Addition Postulate states that m∠A + m∠B = m∠C.

Because the context used is that  m∠AKG + m∠GKB = 180° and m∠GKB + m∠HKB = 180°, it would be using the Definition of Supplementary Angles.

So Becky is the one who is incorrect.

7 0
2 years ago
Callum is walking 270 miles to raise money for cancer research. He plans to walk 1/9 of the distance each day. After 7 days, how
Dmitry_Shevchenko [17]
270-(7/9x270)=60miles
7 0
3 years ago
Find the area cut out of the cylinder x2 z2=9 by the cylinder x2 y2=9.
Digiron [165]
The cylinder is symmetric across the plane y=0, so we need only consider half of the cut-out region.

This region can be parameterized by

\mathbf r(r,\theta)=(r\cos\theta,\sqrt{9-r^2\cos^2t},r\sin\theta)

with 0\le\theta\le2\pi and 0\le r\le3. Then the area of this half is given by the surface integral

\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=3}\left\|\mathbf r_r\times\mathbf r_\theta\right\|\,\mathrm dr\,\mathrm d\theta
=\displaystyle\int_0^{2\pi}\int_0^3\frac{3r}{\sqrt{9-r^2\cos^2\theta}}\,\mathrm dr\,\mathrm d\theta
=36

Doubling this gives a total area of 72.
6 0
3 years ago
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