I believe it would be 60*3.5. I apologize if this information is wrong.
See the attached image! Thanks!
Answer:
F= = 3.18 * 10^3 N
Explanation:
information given:
m= 40.5 kg
a= seven times gravity so we have
a= 7 g
where
gravity = g =9.8 m/s2
F= m*a
F= (40.5) * 7g
a = 7 g = (7) (9.8) = 68.6 m/s2
There are two forces acts on gymnsat
Where ,w is the weight of Gymnsat
F(net) = F - mg
F- mg = ma
F = mg+ma
so
F= m ( g + a)
F = (40.5) [9.8+ 68.6 ]
F = 3.18 * 10^3 N
Answer:
the magnitude of A is 3.577
Explanation:
According to the question it is given that there is a magnitude of 8.0 m that added to the vector A that lies on x axis also the sum of two vectors would be third vector by considering the y axis and the magnitude is the twice of the magnitude B
The computation of the magnitude of A is shown below:

A = 3.577
Hence, the magnitude of A is 3.577
Answer:
1.571 is the required ratio
Solution:
As per the question:
Pressure, P = 
Volume, V = 
Volume,V' = 
(a) To calculate the final pressure:
In adiabatic compression:




(b) From the eqn of ideal gas:
PV = nRT
We can write:

where
T' = Final temperature
T = Initial temperature
Thus

