The minimum stopping distance when the car is moving at 32.0 m/s is 348.3 m.
<h3>
Acceleration of the car </h3>
The acceleration of the car before stopping at the given distance is calculated as follows;
v² = u² + 2as
when the car stops, v = 0
0 = u² + 2as
0 = 15² + 2(76.5)a
0 = 225 + 153a
-a = 225/153
a = - 1.47 m/s²
<h3>Distance traveled when the speed is 32 m/s</h3>
If the same force is applied, then acceleration is constant.
v² = u² + 2as
0 = 32² + 2(-1.47)s
2.94s = 1024
s = 348.3 m
Learn more about distance here: brainly.com/question/4931057
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<span>The gravity of earth depends on the magnetism from its core. as this magnetism increases, the magnitude of the gravity increases.</span>
Answer:
rock will hit the ground at the same time.
Explanation:
given,
Jan throws rock vertically downward with some initial velocity(v).
Len throw rock at an angle of 30° with initial velocity(2 v) twice than the Jan
to find whose rock will hit the ground first.
it is given that rock is identical
now,
vertical component of velocity of the rock
= v₂ sin θ
= v₂ sin 30°
=
= v
hence the vertical velocity of the Len is same as that of Jan so the rock will hit the ground at the same time.
By chromatography it's the answer