When they meet the 40-kg boy will have moved a distance of 6 m.
Displacement of the 40 kg boy
The displacement of the 40 kg boy is calculated from the principle of center mass.
X(40 kg) = (60 x 10 m + 40 x 0)/(40 kg + 60 kg)
X(40 kg) = (600)/(100) = 6 m
X(60 kg) = (60 x 0 + 40 x 10 m)/(40 kg + 60 kg)
X(60 kg) = (400)/(100) = 4 m
Thus, when they meet the 40-kg boy will have moved a distance of 6 m.
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<span>The thermal energy is the work done by friction. If Justin is at rest intially, his potential energy is MGH. Hence we have 30* 9.8*8 = 2352N. Where m is mass, g accleration due to gravity, and h is the height. When he gets to the bottom of the slide, his potential energy is converted to usable kinetic energy, so we have 1/2 mv^2. We end up with 1/2 * 30 * (11)^2 = 1815N. He started with 2352N and ended up with 1815N. Hence the thermal energy is 2352 - 1815 = 537N.</span>
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