Answer:
In horses,the coat color black is dominant (B) over chestnut (b). short hair is dominant (S) over long (s). in a cross between a homozygous black short-haired male and a brown homozygous long-haired female, what would be the phenotype ratio for the f1 generation?
BBSS x bbss= BbSs, BbSs, BbSs and BbSs
4:0
Explanation:
From the above crossing, it could be deduced that all offspring produced are black dominant heterozygous short hair
Answer:
6 chromosomes each
Explanation:
Meiosis is the cell division that results in daughter cells with a reduced number of chromosomes (by half). Meiosis is used only by sexually-reproducing organisms to produce gametes. Since meiosis reduces the chromosomal number, it occurs in a two-step division process viz: Meiosis I and Meiosis II.
Meiosis I involves separation of homologous chromosomes (similar but non-identical chromosomes received from each parent). In the Anaphase stage of meiosis 1, each homologous pair of chromosomes that makes the organism diploid (2n) is separated. Hence, the resulting cells of meiosis I will have a reduced chromosome number (haploid,n).
In this case of a diploid frog with 12 number of chromosomes. If a germline cell or reproductive cell divide by meiosis, in meiosis I, each pair of the 6 pairs of homologous chromosomes of the frog will separate into opposite cells. Hence, at the end of meiosis I, each daughter cell will have 6 chromosomes in a haploid state.
In meiosis II, sister chromatids (replicated chromosomes) separate instead. Each separated chromatid becomes a full chromosome in each gamete.
