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xz_007 [3.2K]
3 years ago
6

Are these triangles similar? Why?

Mathematics
2 answers:
uysha [10]3 years ago
6 0
It looks like yes, SSS
Arada [10]3 years ago
3 0

Answer:

Step-by-step explanation:

<Q is common to both triangles.

130 / 40 = 3.25

Call DQ = x

40/130 = x / (x + 72)       Cross multiply

40*(x + 72) = 130*x

40x + 2880 = 130x      Subtract 40 x from both sides

2880 = 90 x                 Divide by 90

x = 32

(72 + 32)/32 = 104/32 = 3,25

The ratios are the same.

Therefore the triangles are similar by SAS

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Simplify.<br> 2 x (3-1) + 3<br> 07<br> 8<br> O 10<br> O 11
myrzilka [38]

Answer:

7

Step-by-step explanation:

2 x (3-1) + 3

Evaluate using PEMDAS

Parenthesis

Exponents

Math and Division ( left to right )

Addition and Subtraction ( left to right )

2 x (3-1) + 3

According to PEMDAS we do the operations inside of the parenthesis first

3 - 1 = 2

We now have: 2 x 2 + 3

Next we do exponents

There are no exponents so let's move on to multiplication and division

There is indeed multiplication so we do it

2 x 2 = 4

We now have: 4 + 3

Finally we do the addition

4 + 3 = 7

The answer is 7

4 0
3 years ago
Could i get help? it would be great!
alexira [117]

Answer:

B. supplementary angles

Step-by-step explanation:

8 0
2 years ago
Becky read 10 books in 4 days.Sarah reads 50 books in 20 days. Are the two girls reading at the same rate
cupoosta [38]
Yes,
10 x 5 = 50
4 x 5 = 20
They both have equal multiples.
5 0
3 years ago
An urn contains 17 white balls and 20 red balls. A sample of four balls is selected at random from the urn. What is the probabil
Minchanka [31]

The probability that the sample of four balls contains two white balls and two red balls is 0.39.

Let E be an event a sample of selecting four balls from an urn are two red balls and two white balls.

According to the given question.

Total number of marbles in an urn = 17 + 20 = 37

Total number of white marbles = 17

Total number of red marbles = 20

Now, the number of ways of selecting four marbles form an urn = ^{37} C_{4}

And, number of ways of selecting 2 white and two red marbles = ^{17} C_{2} \times\ ^{20} C_{2}

As, we know that probability of an event is calculated by taking the ratio of total number of favorable outcomes to the total number of outcomes.

Therefore, the probability that the sample of four balls contains two white balls and two red balls is given by

P(E) = \frac{^{20}C_{2} \times ^{17}C_{2}   }{^{37}C_{4}  }

\implies P(E) = \frac{\frac{20!\times 17!}{2!18!(2!!15!)} }{\frac{37!}{4!33!} }

\implies P(E) = \frac{\frac{20(19)(17)(16)}{2(2)} }{\frac{37(36)(35)(34)}{(4)(3)(2)} }

⇒ P(E) = 5(19)(17)(16)/(37(3)(35)(17))

⇒ P(E) = 19(16)/37(3)(7)

⇒ P(E) = 304/777

⇒ P(E) = 0.39

Hence, the probability that the sample of four balls contains two white balls and two red balls is 0.39.

Find out more information about probability here:

brainly.com/question/11234923

#SPJ4

8 0
2 years ago
Find the GCF of the following monomials.<br><br> -50m4n7 and 40m2n10
Dima020 [189]

Answer:

Assuming you are asking for the Greatest Common Factor (GCF) of -50m^4n^7 and 40m^2n^{10} the answer is:

10m^2n^7

Step-by-step explanation:

To find the GCF we should first find the GCF of the coefficients 50 and 40 which is 10.

After factoring that out we need to take a look at the variable m. In monomial 1 we see that the highest exponent of m is 4 and in the second is 2. When finding GCF we take the smallest of the two exponents which is 2. Therefore the next part of our GCF monomial is m²

If we apply the same rule for n the smallest exponent is 7 resulting in the appending of n^{7} to the answer

After combining each of these GCF of 40 and -50 (10), m^4 and m² (m²), and n^7 and n^10 (n^7) the answer is:

10m^2n^7

7 0
3 years ago
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