The question is incomplete and the complete question is
Suppose that ear length in rabbits is controlled by two additive genes, each of which has two alleles. A true-breeding female (aabb) with 6-cm ears is mated to a true-breeding male (AABB) with 16-cm ears.
Answer:
AABb or AaBB
Explanation:
We know that,
aabb genotype - 6 cm
AABB genotype- 16-cm
To calculate the length of earlobe contributed by each allele in a genotype is :
1. length of aabb/4 or 6/4= 1.5 cm (a and b contribute for 1.5 cm each)
2. Length of AABB/4 or 16/4= 4 cm (A and B contribute for 4 cm each)
Now to have the earlobe to be 13.5 cm long then the genotype must be
13.5 = 4+4+4+1.5 or A+A+B+b or A+a+B+B
Therefore, the genotype will be-either AABb or AaBB
Do u have choices? if one of the choices are 92 thats correct
Answer:
You use the metric system
Explanation:
Its used all around the world and what is supposed to be used for scientific results.
Answer:
A
Explanation:
The The one that is appropriate is A because phytoplankton to fish is like the bacteria that is on the bottom of the floor in the water and the fish could eat that phytoplankton and then your shark and whale could eat the fish and get the phytoplankton so your answer is A
