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3 years ago

A^2+2ab+b^2. solve for a=10 and b=50

1 answer:

3 0

A² + 2ab + b² ; Solve when a=10 & b=50

Simply plug in 10 for a and 50 for b in our given equation :)

(10)² + 2(10)(50) + (50)²

Simplify.

100 + 20(50) + 2500

Simplify.

(100 + 2500) + 1000

Simplify.

2600 + 1000

Simplify.

3600

Hope I helped! :)

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Answer:

Point estimate for the population variance = 3.92 * $10^{-3}$ .

Step-by-step explanation:

We are given that a sample of 5 strings of thread is randomly selected and the following thicknesses are measured in millimeters ;

X X - $Xbar$ $(X-Xbar)^{2}$

1.13 1.13 - 1.188 = -0.058 3.364 * $10^{-3}$

1.15 1.15 - 1.188 = -0.038 1.444 * $10^{-3}$

1.24 1.24 - 1.188 = 0.052 2.704 * $10^{-3}$

1.27 1.27 - 1.188 = 0.082 6.724 * $10^{-3}$

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Therefore, point estimate for the population variance = 3.92 * $10^{-3}$ .

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You can use the Pythagorean Theorem. Which is a^2 + b^2 = c^2.

So now to plug in the equation.

In your case a is 8 and c is 34. So now we need to solve for b.

8 squared is equal to 64.
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Now to plug things in.

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Now subtract 64 from 1156.

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Now do the square root of 1092.

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