ANSWER
EXPLANATION
We want to factor
out of
The first term is already having a factor of
The constant term which is the second term is not having a factor of
so we need to use a trick of multiplying and dividing by the same factor to obtain,
We can now factor
out of the right hand side to obtain,
Let us rewrite the right most fraction using the normal division symbol.
We simplify to obtain,
This further gives us,
✿————✦————✿————✦————✿
The answer is: <u>2(k2−4k)(2c+5)</u>
✿————✦————✿————✦————✿
Step:
* Consider 2ck2+5k2−8ck−20k. Do the grouping 2ck2+5k2−8ck−20k=(2ck2+5k2) +(−8ck−20k), and factor out k2 in the first and −4k in the second group.
* Factor out the common term 2c+5 by using the distributive property.
* Rewrite the complete factored expression.
✿————✦————✿————✦————✿
Answer:
no to both questions, they might numb your gums but im not 100% sure.
Step-by-step explanation:
X (X - 1) = 342
x² - x = 342
x² - x - 342 = 0
X = 19
Answer: 1 over x to the 5th power
Step-by-step explanation: