3 years ago

When 2x^3-3x^2+kx-1 is divided by x-1 the remainder is 2 find k?

Mathematics

1 answer:

Romashka-Z-Leto [24]3 years ago

7 0

Answer:

k = 4

Step-by-step explanation:

The remainder theorem tells you that the remainder from division of f(x) by (x-1) is f(1). Evaluating the expression for x=1 gives ...

2(1³) -3(1²) +k(1) -1 = 2 -3 +k -1 = k -2

We want this to be equal to 2, so ...

k -2 = 2

k = 4

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