When 2x^3-3x^2+kx-1 is divided by x-1 the remainder is 2 find k?
1 answer:
Answer:
k = 4
Step-by-step explanation:
The remainder theorem tells you that the remainder from division of f(x) by (x-1) is f(1). Evaluating the expression for x=1 gives ...
2(1³) -3(1²) +k(1) -1 = 2 -3 +k -1 = k -2
We want this to be equal to 2, so ...
k -2 = 2
k = 4
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8 divided by 2 = 4 hits
So
28 divides by 2 = 14