Question

When 2x^3-3x^2+kx-1 is divided by x-1 the remainder is 2 find k?​

Answer 1

Answer:

  k = 4

Step-by-step explanation:

The remainder theorem tells you that the remainder from division of f(x) by (x-1) is f(1). Evaluating the expression for x=1 gives ...

  2(1³) -3(1²) +k(1) -1 = 2 -3 +k -1 = k -2

We want this to be equal to 2, so ...

  k -2 = 2

  k = 4