Answer:
<em><u>Commensalism</u></em>=Birds that live among cattle to eat insects stirred up by grazing. it
<em><u>Commensalism</u></em>=An Egyptian plover eating bugs off of a giraffe or rhino.
<em><u>Parasitism</u></em>=A tick living on a dog drinking its blood
<em><u>Predation</u></em>=A bear catching and eating a salmon from a river.
<em><u>Predation</u></em>=A bobcat catching and eating a rabbit.
<em><u>Mutualism</u></em>=A clown fish living in the tentacles of an anemone protected from predators.
<em><u>Mutualism</u></em>=Bees gathering nectar and then spreading pollen from a flower.
<em>Parasitism</em>=A tapeworm living in the digestive system of a horse.
The correct answer is fetal Alcohol syndrome.
Fetal Alcohol Syndrome is termed as the worst alcohol spectrum to a maternal.
Answer:
b. All three plants have a common ancestor that had leaves.
Explanation:
Answer:
<em>Corona disease ( </em>There is no specific treatment for disease caused by a novel coronavirus)
Explanation:)
The virus can cause a range of symptoms, ranging from mild illness to pneumonia. Symptoms of the disease are fever, cough, sore throat and headaches. In severe cases difficulty in breathing and deaths can occur.
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<em>HAVE A NICE DAY !</em>
Answer:
(a) Frequency of M = 0.64
Frequency of N = 0.04
Frequency of MN= 0.32
(b) Expected frequencies of M = 0.648
Expected frequencies of MN = 0.304
Expected frequencies of N = 0.048
Explanation:
(a) If random mating takes place in the population, then the expected frequencies are
f(L(M)) = p = 0.8
F(L(N)) = q
q= 1 - p
= 1 - 0.8
= 0.2
Frequency of M = p^2 = ( 0.8)^2 = 0.64
Frequency of N = q^2 = (1-p)^2 = (1 - 0.8)^2 = (0.2)^2 = 0.04
Frequency of MN = 2pq = 2 * 0.8 * 0.2 = 0.32
(b)
F = inbreeding coefficient = 0.05
f(L(M)L(M)) = p^2 + Fpq = (0.8)^2 + 0.05 * 0.8 * 0.2 = 0.648
f(L(M)L(N)) = 2 pq - 2Fpq = 2 * 0.8 * 0.2 - ( 2 * 0.05 * 0.8 * 0.2) = 0.304
f(L(N)L(N)) = q^2 + Fpq = (0.2)^2 + ( 0.05 * 0.8 * 0.2) = 0.048
