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Arte-miy333 [17]
3 years ago
9

A cube of solid aluminum has a volume of 1.00 m3 at 20�C. What temperature change is required to produce a 110 cm3 increase in t

he volume of the cube?
Chemistry
1 answer:
-Dominant- [34]3 years ago
5 0

Answer:

hjumvjbnjhfdfh

Explanation:

ncfjjk 34696454568899877666656788

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DIA [1.3K]

b. a chemical that cannot be broken down or separated into other chemicals
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A tank contains an ideal gas mixture of 5 g of O2 and 8 g of CO2 at 160kPa and specified temperature. If O2 were separated from
erica [24]

Answer:

74 or 74 kPa.

Explanation:

Hello,

In this case, based on the initial information, it is seen that the oxygen and the carbon dioxide form the mixture at 160 kPa, thus, by isolating the oxygen, its pressure will be equal to its initial partial pressure because it gets isolated, hence, we compute its molar fraction as:

x_{O_2}=\frac{5gO_2*\frac{1molO_2}{32gO_2} }{5gO_2*\frac{1molO_2}{32gO_2} +8gCO_2*\frac{1molCO_2}{44gCO_2} } =0.46

Therefore, its initial pressure turns out:

p_{O_2}=160kPa*0.46=73.9kPa

Such pressure will be the oxygen's pressure once it is isolated. Finally, considering the request, the answer will be just 74 (by rounding to the nearest integer and without units).

Best regards.

8 0
3 years ago
Given a solution at 25°C, the [H+] is 3.5 × 10−6 M. Determine the [OH−].
taurus [48]

Answer:

<em>(OH-)=2,86 x10 ^-9 M.</em>

Explanation:

Both pH and pOH have a relationship to belonging to the same aqueous solution: the expression of the Kwater (ionic product of the water Kw) is used:

(H3O+) x (OH-) = 1x10^-14

(3.5 × 10^−6)  x (OH-)= 1x10^-14

(OH-)= 1x10^-14/(3.5 × 10^−6)

<em>(OH-)=2,86 x10 ^-9 M</em>

<em></em>

7 0
3 years ago
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