Question

For the balanced equation shown below, if the reaction of 0.112 grams of

Answer 1

Answer:

The answer is 74.5%.

Explanation:

As we know that % yield=  $\frac{actual yield}{theoretical yield}$ x 100%.

Therefore,

Step 1 Calculate Theoretical yield:

0.112$H_{2}$ x   $\frac{1 mol H_{2} }{2.016 g of H{2} }$    x    $\frac{4 mol H_{2}O }{4 mol H_{2} }$    x  $\frac{18.02 g H_{2}O }{1 mol H_{2}O}$   = 1.001 g $H_{2}O$

Now Step 2

% yield   =  $\frac{actual yield}{theoretical yield}$ x 100% =   $\frac{0.745g}{1.001g}$ = 74.5%