0.1875 mol of Na2CO3 needed to react with the 750 mL of 0.250 M H2SO4.
The given reaction between Na2CO3 and H2SO4 are already balanced.
Na2CO3 + H2SO4 → Na2SO4 + CO2.H2O
First, let us determine the number of moles of H2SO4.
Molarity (mol/L) = number of moles of H2SO4 / volume of H2SO4
0.250 M = number of moles of H2SO4 / [(750 mL)(1 L/1000 mL)]
number of moles of H2SO4 = 0.1875 mol
Then, let us determine the number of moles of Na2CO3 that would react with 0.1875 mol H2SO4.
number of moles of Na2CO3 = moles of H2SO4 * stoichiometric ratio
number of moles of Na2CO3 = 0.1875 mol H2SO4 * (1 mol Na2CO3/ mol H2SO4)
number of moles of Na2CO3 = 0.1875 mol Na2CO3
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Molarity is defined as the ratio of number of moles to the volume of solution in litres.
The mathematical expression is given as:
Here, molarity is equal to 1.43 M and volume is equal to 785 mL.
Convert mL into L
As, 1 mL = 0.001 L
Thus, volume = 
= 0.785 L
Rearrange the formula of molarity in terms of number of moles:
n = 
= 1.12255 mole
Now, Number of moles = 
Molar mass of potassium hydroxide = 56.10 g/mol
1.12255 mole = 
mass in g = 
= 62.97 g
Hence, mass of 
= 62.97 g
Answer:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids)
Explanation:
There are four major classes of biological macromolecules (carbohydrates, lipids, proteins, and nucleic acids), and each is an important component of the cell and performs a wide array of functions. ... Biological macromolecules are organic, meaning that they contain carbon.
In a mixture of gases, the total pressure is equivalent to the aggregate of all the partial pressures of the single element of the gas.
It can be written as 
= P₁ + P₂ + P₃ and so on.
The partial pressure will be:
Option A. 0. 31 atm
Pressure can be estimated by:
<u>PV = nRT</u>
Where,
And,
Solving finally we get,
Therefore, 0.31 atm is the partial pressure of the hydrogen gas.
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