Okay, if the jeans were originally $80, take 40% off of that (40% of 80 is 32) so you’d get 48. Now take 48 and multiply by 1.07 (to get 107% of the $48, to find a percentage you can move the decimal place left 2 digits and multiply), so Justin would pay $51.36 in total.
Answer:
BC
Step-by-step explanation:
A secant is a line which intersects the circle at 2 points
In the given diagram this is BC
Complete question :
Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?
Answer:
61
Step-by-step explanation:
Given the following :
Total number of students = 4 + 1 missing = 5
Score on the four avaliable papers = 60, 62, 56, 57
Average score of the 5 papers = 59.2
Score on missing paper :
Sum of each score / number of papers
Sum of each score = sum of available scores + missing score
Let missing score = m
(60 + 62 + 56 + 57 + m) = 235 + m
Recall:
Average = total sum / number of observations
Hence,
59.2 = (235 + m) / 5
59.2 × 5 = 235 + m
296 = 235 + m
m = 296 - 235
m = 61
Missing score = 61
Parameterize the lateral face

of the cylinder by

where

and

, and parameterize the disks

as


where

and

.
The integral along the surface of the cylinder (with outward/positive orientation) is then




The time it will take to fill the vat if both pipes are left open is = 4.3 hours
<h3>Calculation of time taken to fill vat</h3>
The number of pipes a vat has = 2
The time it takes the inlet pipe to fill the vat = 3hrs
The time it takes the outlet pipe to empty the vat= 10hrs
Therefore, the time it will take to fill the vat if both pipes are left open is;
1/t = 1/3-1/10
1/t = 7/30
Make t the subject of formula,
t = 30/7
t= 4.3 hours
Learn more about hours here:
brainly.com/question/291457
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